I have been researching and the proximal operator seems to be defined as:
$$\DeclareMathOperator*{\argmin}{argmin}\DeclareMathOperator{\prox}{prox} \prox_f(v)=\argmin_x\left(f(x)+\frac{1}{2}\|x-v\|^2_2\right)$$
I have found it stated several times that this is always a convex problem with a unique minimizer. I have not, however, been able to find a proof of this statement. So, why does the proximal operator have a unique solution?
In addition, this article (link credit Mark L. Stone, see comments) hints that $f(x)$ must be convex for the proximal operator to be a convex problem. If this condition is required by the proof, why would someone use proximal optimization methods over simple gradient descent?