If $X$ is distributed normally $N(\mu,\sigma^2)$ then the variable $Y = \exp(X)$ is lognormally distributed.

If the variable $Y$ is multiplied by some constant $C$:

$$D = CY$$

Is the variable $D$ also lognormally distributed?

Yes it is since:

$$D = C\exp(X)$$ $$\log(D) = \log(C\exp(X)) = \ln(C) + X$$ $$X + \ln(C) \sim N(\mu + ln(C), \sigma^2)$$ $$D \sim \ln N(\mu + ln(C), \sigma^2)$$

  • 2
    $\begingroup$ If $Z$ is normally distributed, what's the distribution of $Z+a$? $\endgroup$
    – Glen_b
    Jul 19, 2016 at 10:51
  • $\begingroup$ $Z$ will be normal $N(\mu_Z+\alpha,\sigma_Z^2)$. So I suppose this means that $D$ is my question is lognormally distributed. $\endgroup$
    – egg
    Jul 19, 2016 at 10:53
  • $\begingroup$ Yes, Z+a is normal so exp(Z+a) is lognormal. If you want to answer yourself, go ahead. If not I'll probably put an answer sometime soon $\endgroup$
    – Glen_b
    Jul 19, 2016 at 22:38

1 Answer 1


The multiple of a lognormal variable is also lognormally distributed.

$$X \sim \mathcal{N}(\mu,\sigma^2)$$ $$Y = e^X$$ $$CY = Ce^X$$

The random variable $CY$ is lognormally distributed since:

$$\ln(CY) = \ln(Ce^X)=\ln(C)+\ln(e^X)=\ln(C)+X$$

Note that:

$$\ln(C) + X \sim \mathcal{N}(\mu + \ln(C), \sigma^2)$$

Therefore $CY$ is lognormally distributed $CY \sim \ln \mathcal{N}(\mu + \ln(C), \sigma^2)$


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