1
$\begingroup$

I am performing an experiment to identify significance in certain factors and covarites. I am using an ANCOVA model with 6 regression covariates, 1 treatment factor and a blocking factor and am including interactions between the covariates and the treatment factor. Are my sums of squares(via aov function) still valid if I get unestimable coefficients in R? I am not interested in making inference on the coefficients, so I was thinking whether non-estimable coefficients can just be ignored.

EDIT for example to MDEWEY comment.

data.frame(x1,x2,x3,x4,x5,x6)
    x1 x2 x3 x4 x5 x6
1   12  0  0  0  0  0
2   12  0  0  0  0  0
3   12  0  0  0  0  0
4   12  0  0  0  0  0
5    0 12  0  0  0  0
6    0 12  0  0  0  0
7    0 12  0  0  0  0
8    0 12  0  0  0  0
9    0  0 12  0  0  0
10   0  0 12  0  0  0
11   0  0 12  0  0  0
12   0  0 12  0  0  0
13   0  0  0 12  0  0
14   0  0  0 12  0  0
15   0  0  0 12  0  0
16   0  0  0 12  0  0
17   0  0  0  0 12  0
18   0  0  0  0 12  0
19   0  0  0  0 12  0
20   0  0  0  0 12  0
21   0  0  0  0  0 12
22   0  0  0  0  0 12
23   0  0  0  0  0 12
24   0  0  0  0  0 12
25   6  6  0  0  0  0
26   6  6  0  0  0  0
27   6  6  0  0  0  0
28   6  6  0  0  0  0
29   6  0  6  0  0  0
30   6  0  6  0  0  0
31   6  0  6  0  0  0
32   6  0  6  0  0  0
33   6  0  0  6  0  0
34   6  0  0  6  0  0
35   6  0  0  6  0  0
36   6  0  0  6  0  0
37   6  0  0  0  6  0
38   6  0  0  0  6  0
39   6  0  0  0  6  0
40   6  0  0  0  6  0
41   6  0  0  0  0  6
42   6  0  0  0  0  6
43   6  0  0  0  0  6
44   6  0  0  0  0  6
45   0  6  6  0  0  0
46   0  6  6  0  0  0
47   0  6  6  0  0  0
48   0  6  6  0  0  0
49   0  6  0  6  0  0
50   0  6  0  6  0  0
51   0  6  0  6  0  0
52   0  6  0  6  0  0
53   0  6  0  0  6  0
54   0  6  0  0  6  0
55   0  6  0  0  6  0
56   0  6  0  0  6  0
57   0  6  0  0  0  6
58   0  6  0  0  0  6
59   0  6  0  0  0  6
60   0  6  0  0  0  6
61   0  0  6  6  0  0
62   0  0  6  6  0  0
63   0  0  6  6  0  0
64   0  0  6  6  0  0
65   0  0  6  0  6  0
66   0  0  6  0  6  0
67   0  0  6  0  6  0
68   0  0  6  0  6  0
69   0  0  6  0  0  6
70   0  0  6  0  0  6
71   0  0  6  0  0  6
72   0  0  6  0  0  6
73   0  0  0  6  6  0
74   0  0  0  6  6  0
75   0  0  0  6  6  0
76   0  0  0  6  6  0
77   0  0  0  6  0  6
78   0  0  0  6  0  6
79   0  0  0  6  0  6
80   0  0  0  6  0  6
81   0  0  0  0  6  6
82   0  0  0  0  6  6
83   0  0  0  0  6  6
84   0  0  0  0  6  6
85   4  4  4  0  0  0
86   4  4  4  0  0  0
87   4  4  4  0  0  0
88   4  4  4  0  0  0
89   4  4  0  4  0  0
90   4  4  0  4  0  0
91   4  4  0  4  0  0
92   4  4  0  4  0  0
93   4  4  0  0  4  0
94   4  4  0  0  4  0
95   4  4  0  0  4  0
96   4  4  0  0  4  0
97   4  4  0  0  0  4
98   4  4  0  0  0  4
99   4  4  0  0  0  4
100  4  4  0  0  0  4
101  4  0  4  4  0  0
102  4  0  4  4  0  0
103  4  0  4  4  0  0
104  4  0  4  4  0  0
105  4  0  4  0  4  0
106  4  0  4  0  4  0
107  4  0  4  0  4  0
108  4  0  4  0  4  0
109  4  0  4  0  0  4
110  4  0  4  0  0  4
111  4  0  4  0  0  4
112  4  0  4  0  0  4
113  4  0  0  4  4  0
114  4  0  0  4  4  0
115  4  0  0  4  4  0
116  4  0  0  4  4  0
117  4  0  0  4  0  4
118  4  0  0  4  0  4
119  4  0  0  4  0  4
120  4  0  0  4  0  4
121  4  0  0  0  4  4
122  4  0  0  0  4  4
123  4  0  0  0  4  4
124  4  0  0  0  4  4
125  0  4  4  4  0  0
126  0  4  4  4  0  0
127  0  4  4  4  0  0
128  0  4  4  4  0  0
129  0  4  4  0  4  0
130  0  4  4  0  4  0
131  0  4  4  0  4  0
132  0  4  4  0  4  0
133  0  4  4  0  0  4
134  0  4  4  0  0  4
135  0  4  4  0  0  4
136  0  4  4  0  0  4
137  0  4  0  4  4  0
138  0  4  0  4  4  0
139  0  4  0  4  4  0
140  0  4  0  4  4  0
141  0  4  0  4  0  4
142  0  4  0  4  0  4
143  0  4  0  4  0  4
144  0  4  0  4  0  4
145  0  4  0  0  4  4
146  0  4  0  0  4  4
147  0  4  0  0  4  4
148  0  4  0  0  4  4
149  0  0  4  4  4  0
150  0  0  4  4  4  0
151  0  0  4  4  4  0
152  0  0  4  4  4  0
153  0  0  4  4  0  4
154  0  0  4  4  0  4
155  0  0  4  4  0  4
156  0  0  4  4  0  4
157  0  0  4  0  4  4
158  0  0  4  0  4  4
159  0  0  4  0  4  4
160  0  0  4  0  4  4
161  0  0  0  4  4  4
162  0  0  0  4  4  4
163  0  0  0  4  4  4
164  0  0  0  4  4  4
$\endgroup$
3
  • $\begingroup$ Would it not be wise to find out why your model cannot be estimated first? $\endgroup$
    – mdewey
    Aug 21, 2016 at 10:46
  • $\begingroup$ @mdewey I know it is because of the regression covariates. When I add the last regression covariate, the alias() shows me that x6 is a linear combination of the intercept and x1,x2,x3,x4,x5. This linear dependence is quite obvious by the design. x1,x2,x3,x4,x5,x6 contain only 4 values each (0,4,6,12) and they are in a pattern as updated. $\endgroup$ Aug 21, 2016 at 17:22
  • $\begingroup$ But why would it matter, if I am not interested in what the coefficients of the linear model mean(added inside question). I am more interested in considering x1,x2,x3,x4,x5,x6 together as an individual vector space on its own. $\endgroup$ Aug 21, 2016 at 17:28

0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Browse other questions tagged or ask your own question.