Suppose I have an unfair coin, and the probability of flip a head (H) is p, probability of flip a tail (T) is (1-p).
If I flip the coin 6 times, wondering if the probability of HTT???, and the probability of THT???, and the probability of TTH??? are the same? Suppose each flip is independent. ? means do not care if head or tail. Thanks.
I calculated they are the same, ask here to get advice from expert if my calculation is correct.
Yes, all the three events are independent. The cumulative law gives you:
t * h *t = h * t * t = t* t* h
If you enter number you will get:
0.3 * 0.7 * 0.3 = 0.7 * 0.3 * 0.3 = 0.3 * 0.3 * 0.7 = 0.063
Edit: It does not matter what the first three times are because of the law of conditional probability.
P(A $\bigcap$ B) = P(A) * P(B) $\Leftrightarrow$ P(A) = $\frac{P(A)P(B)} {P(B)}$ = $\frac{P(A)\bigcap P(B)} {P(B)}$ = P(A|B)
You can also take an example. All equations have the same product.
0.3 * 0.7 * 0.3 *0.3 ^ 3 = 0.001701
0.7 * 0.3 * 0.3 *0.3^3= 0.001701
0.3 * 0.3 * 0.7 * 0.3^3= 0.001701
The last could be any combination of head and tail. 0.3^3 is just an example, but it works out equally if one or two or three of the variables is 0.7.
0.3 * 0.7 * 0.3 * 0.3 ^ 3 other than 0.3 ^ 3 * 0.3 * 0.7 * 0.3? The other comment is, not sure why you are using 0.3^3, the last 3 times could be any combinations of head and tail.
$\endgroup$
– Lin Ma
Oct 5 '16 at 6:28
???HTT, ???THT and ???TTH? And their probability is the same as HTT???, THT??? and TTH??? (where I care first 3 flip results, and do not quite care last time flips)?
$\endgroup$
– Lin Ma
Oct 5 '16 at 7:09
