Central Limit Theorem for Markov Chains $\newcommand{\E}{\mathbb{E}}$$\newcommand{\P}{\mathbb{P}}$The Central Limit Theorem (CLT) states that for $X_1,X_2,\dots$ independent and identically distributed (iid) with $\E[X_i]=0$ and $\operatorname{ Var} (X_i)<\infty$,
the sum converges to a normal distribution as $n\to\infty$:
$$
\sum_{i=1}^n X_i \to N\left(0, \sqrt{n}\right).
$$
Assume instead that $X_1,X_2,\dots$ form a finite-state Markov chain with a stationary distribution $\P_\infty$ with expectation 0 and bounded variance.
Is there a simple extension of CLT for this case? 
The papers I've found on CLT for Markov Chains generally treat much more general cases. I would be very grateful for a pointer to the relevant general result and an explanation of how it applies.
 A: The "usual" result for Markov Chains is the Birkhoff Ergodic Theorem, which says that 
$$\frac{1}{n}\sum_{i=1}^nf(X_i)\rightarrow E_{\pi}[f],$$
where $\pi$ is the stationary distribution, and $f$ satisfies $E|f(X_1)|<\infty$, and the convergence is almost-sure. 
Unfortunately the fluctuations of this convergence are generally quite difficult. This is mainly due to the extreme difficulty of figuring out total variation bounds on how quickly $X_i$ converge to the stationary distribution $\pi$. There are known cases where the fluctuations are analogous to the CLT, and you can find some conditions on the drift which make the analogy hold: On the Markov Chain Central Limit Theorem -- Galin L. Jones (See Theorem 1).
There are also stupid situations, for example a chain with two states, where one is absorbing (i.e. $P(1\rightarrow 2)=1$ and $P(2\rightarrow 1)=0$. In this case there are no fluctuations, and you get convergence to a degenerate normal distribution (a constant). 
A: Alex R.'s answer is almost sufficient, but I add a few more details. In On the Markov Chain Central Limit Theorem – Galin L. Jones, if you look at theorem 9, it says,

If $X$ is a Harris ergodic Markov chain with stationary distribution
  $\pi$, then a CLT holds for $f$ if $X$ is uniformly ergodic and
  $E[f^2] < \infty$.

For finite state spaces, all irreducible and aperiodic Markov chains are uniformly ergodic. The proof for this involves some considerable background in Markov chain theory. A good reference would be Page 32, at the bottom of Theorem 18 here. 
Hence, the Markov chain CLT would hold for any function $f$ that has a finite second moment. The form the CLT takes is described as follows.
Let $\bar{f}_n$ be the time averaged estimator of $E_{\pi}[f]$, then as Alex R. points out, as $n \to \infty$,
$$\bar{f}_n = \frac{1}{n} \sum_{i=1}^n f(X_i) \overset{\text{a.s.}}{\to} E_\pi[f].$$
The Markov chain CLT is
$$\sqrt{n} (\bar{f}_n - E_\pi[f]) \overset{d}{\to} N(0, \sigma^2), $$
where
$$\sigma^2 = \underbrace{\operatorname{Var}_\pi(f(X_1))}_\text{Expected term} + \underbrace{2 \sum_{k=1}^\infty \operatorname{Cov}_\pi(f(X_1), f(X_{1+k}))}_\text{Term due to Markov chain}. $$
A derivation for the $\sigma^2$ term can be found on Page 8 and Page 9 of Charles Geyer's MCMC notes here
