1
$\begingroup$

In page 5 of chapter 2 of Gaussian Process for machine learning [1], the author mentions the following:

$p(f_*| {\bf x_*}, X, {\bf y}) = \int p(f_*| x_*, {\bf w} )\space p(w | X, {\bf y} ) = \mathcal{N}\space(\frac{1}{\sigma_n^2} {\bf x_*}^T A^{-1}X {\bf y}, {\bf x_*}^T A^{-1} {\bf x_*})$

Is it possible to prove the above without rigrous math? Given that both $p(f_*| x_*, {\bf w} ) $ and $p(w | X, {\bf y} )$ are gaussian ditributions. The distributions are given in equations 2.3 and 2.8 of http://www.gaussianprocess.org/gpml/chapters/RW2.pdf [2] .

[1] http://www.gaussianprocess.org/gpml/

[2] http://www.gaussianprocess.org/gpml/chapters/RW2.pdf

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.