0
$\begingroup$

This question already has an answer here:

If yes why is it the case that it have this property? There must be some mathematical proof or intuitive understanding in that case.

$\endgroup$

marked as duplicate by Xi'an, Michael M, whuber Nov 25 '16 at 17:22

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

  • 2
    $\begingroup$ How do you define mean deviation? $\endgroup$ – Xi'an Nov 25 '16 at 15:36
  • 2
    $\begingroup$ There is a proof on the Wikipedia page: en.wikipedia.org/wiki/Average_absolute_deviation $\endgroup$ – Erik Nov 25 '16 at 15:38
  • 1
    $\begingroup$ The duplicate concerns a generalization: the mean deviation corresponds to $n=1$ while the SD corresponds to $n=2$. $\endgroup$ – whuber Nov 25 '16 at 17:23