I am resolving an anova one-way exercise. But I am doubtful because when using the F-table to get the p-value, I am getting a probability around 2.2 (an obvious error), but if I use a calculator the probability is 0.042.
I have an independent variable with 4 levels. The mean and standard deviation are this:
N Mean Standard Deviation 10 4.3 2.2 10 3.8 1.6 10 4.9 1.9 10 6.3 2.1
I did these calculations:
Grand mean = 4.8.
Sum of squares between groups = 35.07.
Sum of squares within groups = 138.7.
The degrees of freedom between groups is 3, the degree of freedom within groups is 36.
So with this I get a value of 3.
With this f value I check the f table for a 5% of significance level, using a degree of freedom of 3 in the numerator and 36 in the denominator and the value in the table is around 2.2. So I'm not understanding why I get 2.2 and the calculator gives 0.042. Do you have any idea?