8
$\begingroup$

I am a little confused over formula for calculating covariance in Gaussian process (addition of variance always confuses me as it is not always explicitly denoted). The origin of confusion is that the formulas are given in Pattern Recognition and Machine Learning by Bishop and Gaussian process for Machine Learning by Rasmussen are different.

Mean of GP is given by relation: $$\mu = K(X_*, X)[K(X,X)+\sigma^2\mathrm{I}]^{-1}y$$

Variance according to Bishop (page no: 308) is: $$\Sigma = [K(X_*, X_*)+\sigma^2] - K(X_*, X)[K(X,X)+\sigma^2\mathrm{I}]^{-1}K(X, X_*)$$

Variance according to Rasmussen (page no: 16) is: $$\Sigma = K(X_*, X_*) - K(X_*, X)[K(X,X)+\sigma^2\mathrm{I}]^{-1}K(X, X_*)$$

My doubt is whether the variance is there or not in first term in RHS for covariance matrix $\Sigma$. Or have I messed up things?

Let me know if I need to provide more information.

$\endgroup$
8
$\begingroup$

Noise parameter, $\sigma^2$, is the parameter of the likelihood function a.k.a noise function.

The one with $+\sigma^2$ is the variance of $y$ (observation). The one without is the variance of $f$ (latent variable = observation - noise). So they are off from each other by $\sigma^2$ which is the same for all values of input variable $x$.

The formulas look right to me. As you see the variance of $y$ (the noiseless observation) is also dependent on the noise parameter. It make sense too. Your estimation of noise would affect the uncertainty estimate (i.e. variance) of the (noiseless) latent variable.

To avoid confusion I would refer to them by $\mathrm{var}(y)$ and $\mathrm{var}(f)$.

One more thing: the two expressions you denoted by $\Sigma$ are scalars, not matrices. The covariance matrix is $K$ not $\Sigma$. $\Sigma$ is variance not covariance since it is about a single $1$-D variable (either $y$ or $f$).

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.