# Simulating from this density?

How can I simulate from the density $f(x)=x^2\phi(x)$? Where $\phi$ is the standard normal density. Preferably directly, without using MCMC.

• Could you provide more details on where you are stuck? This is a simple density for which standard methods like accept-reject or ratio of uniform work. Mar 5 '17 at 9:27
• @Xi'an I was just thinking that there might be a magic trick to simulate directly from this distribution without having to go for less efficient methods. Mar 5 '17 at 9:30
• accept-reject and ratio of uniform algorithms are "efficient" enough to be the methods behind the standard simulators for most classical distributions. Mar 5 '17 at 9:37
• @Xi'an Yes! But not as efficient as direct simulation! Mar 5 '17 at 11:21
• @Glen_b In my case, I just need to be able to simulate from that distribution. An efficient method is desirable. Mar 5 '17 at 11:32

[The cdf of this variable is $\Phi(x)-x\phi(x)$ but that's not likely to yield a convenient way to generate via the inverse-cdf method.]

Transformation is fairly easy -- if $X$ has the specified density, then $Y=\frac12 X^2$ has a simple, well-known distribution that is often available in statistical computing environments already (it is in R for example; it should also be available in many libraries)

If you're unfamiliar with transforming random variables, it's covered in detail in many places - see here for example, or here, and in this question CDF of transformed random variable; the calculations are straightforward substitution in a formula and one very simple differentiation. There's a detailed (and related) example discussed here.

So if you can generate from the appropriate distribution for $Y$, then $X=Z\sqrt{2Y}$ (where $Z$ is a random sign, ie. $\pm 1$ with equal probability) will have the distribution you're after.

(Actually the factor of $2$ could be incorporated in the original generation by changing the scale parameter, which may be slightly more convenient, avoiding the need to double $Y$ before taking the square root - because it would have been doubled at the previous stage)

We can see that this method works; here's a histogram of a large sample generated using this approach, and the functional form of the density you specified drawn over the top: While this is very convenient, if efficiency is an issue it's not likely to be faster than a well-chosen variant of the accept-reject method (ratio-of uniforms counts as one possible variant of accept-reject; it might be suitable particularly if accompanied by its own transformation -- in particular, one not requiring a square root, in the interests of speed)