I suspect that if there are many unimportant outliers, trimmed k-mean clustering should be employed.

Am I on the right track?

  • $\begingroup$ Yes. The original trimmed $k$-means1997 paper by Cuesta-Albertos et al. did exactly that. $\endgroup$
    – usεr11852
    May 14, 2017 at 0:28


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