17
$\begingroup$

Is the average of multiple positive-definite matrices necessarily positive-definite or positive semi-definite? The average is element-wise average.

$\endgroup$
1
  • 3
    $\begingroup$ Average is just sum followed by scaling. Is this true for each of those? $\endgroup$
    – user541686
    May 30, 2017 at 1:29

2 Answers 2

27
$\begingroup$

Yes, it is. jth asnwer is correct (+1) but I think you can get a much simple explanation with just basic Linear Algebra.

Assume $A$ and $B$ are positive definite matrices for size $n$. By definition this means that for all $u \in R^n$, $0 < u^TAu$ and $0 < u^TBu$. This means that $0 < u^TAu + u^TBu$ or equivalently that $ 0 < u^T(A+B)u$. ie. $(A+B)$ has to be positive definite.

$\endgroup$
0
15
$\begingroup$

Of course. The set of positive definite matrices forms a cone, meaning it is closed under positive linear combinations and scaling.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.