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I'm reading the public draft (pdf) of the 2nd edition of Sutton&Barto's RL Book.

There are a few things I don't understand about the Off-policy n-step Sarsa method described in the book. You can find the pseudo-code at page 159 (177) of the pdf I linked above.

Here's a picture of the pseudo-code for your convenience:

enter image description here

Here are the 3 things I don't understand:

  1. $\rho$ considers the actions $A_{\tau+1},\ldots,A_{\tau+n-1}$. Shouldn't it also consider $A_{\tau+n}$?
  2. In the third to last line, $\rho$ multiplies both $G$ and $Q(S_\tau,A_\tau)$. Shouldn't it multiply just $G$?
  3. The second to last line says that $\pi$, if being learned, must be $\epsilon$-greedy wrt $Q$ (with $\epsilon>0$). I don't understand the reason of this restriction. Can't $\pi$ be greedy just like in Q Learning? The exploration is already taken care of by $\mu$.
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  • $\begingroup$ Regarding point 2, I am having the same doubt, I actually asked the question before I found yours: ai.stackexchange.com/questions/11676/… $\endgroup$ – Antoine Savine Apr 5 '19 at 14:31
  • $\begingroup$ I even messaged Rich Sutton, hopefully we get an answer. $\endgroup$ – Antoine Savine Apr 5 '19 at 14:31
  • $\begingroup$ Were you able to clarify the question (since you asked yourself the same question two years ago :)? $\endgroup$ – Antoine Savine Apr 5 '19 at 14:32
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1) Aτ+n is omitted since it is the state at horizon for the n-step update and estimated value for its action-value will be used so weighting by its importance ratio is skipped.

2) I was wondering the same - it even makes my action-values to grow to infinity(with rewards -1.0 for all steps and 1.0 for goal reached). My implementation for n-Step Q(σ) estimation works fine with σ=1 matching the n-Step Tree Backup as expected but for σ=0 it reproduces the same problem with non-stop growing state-action-values as in the simple Off-Policy n-Step Sarsa.

3) If it is deterministic greedy then all its action probabilities for a given state will be 0 instead of the greedy action(for which will be 1.0) and thus the importance ratio product will be non-zero only when the actions chosen by the behavior policy will match the greedy policy - I don't think this will help exploration.

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