0
$\begingroup$

I am reading a paper, and it is said "state observationprobability densities were single mixture Gaussian observation densities". My question is: Isn't a single mixture gaussian the same that a regular 1-D gaussian?

$\endgroup$
  • 1
    $\begingroup$ I single mixture sounds to me like a mixture of two different Gaussian distributions which may not look like a single Gaussian distribution at all. It is likely to be bimodal. The existence of a mean and covariance matrix can happen with a mixture distribution without it being a single Gaussian distribution. $\endgroup$ – Michael R. Chernick Aug 14 '17 at 16:47
1
$\begingroup$

Single mixture gaussian does not seem to be an accepted term, but it is probably equivalent to a regular gaussian distribution, either univariate or multivariate (more context is needed to tell which).

Without knowing which paper you are talking about, I would guess that the authors modeled state observation distribution as a single gaussian, but wanted to hint that the model could be generalized to a gaussian mixture with $n > 1$ components, even though they did not do so.

edit: paper is here

After reading the context in the paper, I am more confident that the authors intended single mixture gaussian to just mean a normal gaussian distribution, as they talk about a single mean and covariance matrix.

$\endgroup$
  • $\begingroup$ Thanks! But isn't the author talking here about a multivariate gaussian with every dimension being the dimension of the feature vector (in this case, 6 AR coefficients and RMS, so dimension 7)? $\endgroup$ – Moltimor Aug 14 '17 at 20:31

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.