I have a question that seems easy but kind of hard to calculate (at least for me):
There are three boxes of balls, one with red balls, one with blue balls, one with green balls. Draw three balls from one box, (so all three balls must be the same color) show them to 3 person P1 P2 P3 from distance and get their answers.
P1 P2 P3 have probabilities of correct identification P1=0.9 P2=0.8 P3=0.7
For the 1st ball, P1 says it is Blue, P2 says it is Blue, P3 says it is Red
For the 2nd ball, P1 says it is Blue, P2 says it is Green, P3 says it is Blue
For the 3rd ball, P1 says it is Red, P2 says it is Blue, P3 says it is Green
One thing in particlar that I don't understand is how to calculate the probability of all three balls being Blue? Is this equal to draw one ball and let P1 P2 P3 identify /measure three times?