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Suppose that we have a discrete random variable X with support S={1,2,3}, with probabilities of, respectively, 0.1, 0.4, 0.5. How could I find the PDF of Y if Y = (X+10)^2?

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Fill in the missing entries in this table: $$\begin{eqnarray*} X &\quad Y\\ 1 &\quad (1+10)^2\\ 2 &\quad ?\\ 3 &\quad ?\\ \end{eqnarray*}$$ Now, $\Pr(X=1)=0.1$, so $\Pr(Y=(1+10)^2)=\dots$?

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