1
$\begingroup$

Was reading through my lecture slides and I saw this question enter image description here

I am not sure what or how the prof approached this problem after step 6.

It'd be greatly appreciated if anyone can tell me what's going on here.

$\endgroup$
0
$\begingroup$

You have 12 in your sixth arrow should this be 1/2? If this is a typo (either in your slides or this post) then the rest of the problem seems straightforward, multiply by 2 to get $2y(x)=y(x+1) +y(x-1)$ then $2y(x) = y(x) + y(x)$ and rearrange to get the 7th arrow. Then the problem is a matter of fitting an affine function to 2 points.

$\endgroup$
  • $\begingroup$ yeah, the prof had a typo in his slides which confused me a lot! thanks $\endgroup$ – bleepblop Nov 12 '17 at 16:31

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.