Let $y_{t}$ be a scalar stationary stochastic process with its Wold representation

$y_{t} = \mu_{t} + \sum_{k = 0}^{\infty} \phi_{k}\epsilon_{t-k}$.

I understand that the theorem says that $\sum_{k=0}^{\infty} \phi_{k}^2$ is finite. Although, we if assume that $Var(\epsilon_{t}) = \sigma^2, \forall t$, can we state that $\sum_{k=0}^{\infty} |\phi_{k}|$ is also finite?

I don't think so, but I would like some clarification. For example, if we let $\mu_{t} = 0, \forall t$ and $\phi_{k} = 1/k$ for every $k$, then the above conjecture fails. What do you guys think? Is this a valid counterexample? Thanks in advance!

  • $\begingroup$ I don't see how $\operatorname{Var}(\epsilon_t) = \sigma^2$ has anything to with whether $\sum_{k=0}^{\infty} |\phi_{k}|$ or $\sum_{k=0}^{\infty} |\phi_{k}|^2$ are finite. $\endgroup$ Commented Dec 14, 2017 at 19:24

1 Answer 1


Yes, that's a valid counterexample.

It might be fun/useful to think about this more broadly. An equivalent question to yours might be, "Are there sequences in $ℓ_2$, the space of square summable sequences, that aren't in $ℓ_1$, the space of absolutely convergent sequences?

Those sums you have are basically the p-norm.

The p-norm and its generalizations:

  • In a finite, $n$ dimensional vector space, the the p-norm is: $$ \|\phi \|_p = \left( \sum_{k=1}^n |\phi_k|^p \right) ^\frac{1}{p}$$
  • In a countably infinite $ℓ_p$ space, the p-norm is: $$ \|\phi \|_p = \left( \sum_{k=1}^\infty |\phi_k|^p \right) ^\frac{1}{p}$$
  • In $L_p$ spaces, the generalization for the p-norm is: $$ \|f\|_p = \left( \int_S |f|^p d \mu\right)^\frac{1}{p}$$

As described in this answer, $f(x) = \frac{1}{x}$ for $x >0$ and $f(0)=0$ is an example of a function that is in $L_2$ but not $L_1$.

  • $\begingroup$ Thanks! I have already some stuff on Lp spaces but I didn't see the link! That kind of stuff you learn in different course along life and fail to connect dots. Very welcome answer! $\endgroup$ Commented Dec 14, 2017 at 19:30

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