For regression problem, I have seen people use "coefficient of determination" (a.k.a R squared) to perform model selection, e.g., finding the appropriate penalty coefficient for regularization.

However, it is also common to use "mean squared error" or "root mean squared error" as a measure of regression accuracy.

So what is the main difference between these two? Could they be used interchangeably for "regularization" and "regression" tasks? And what are the main usage of each in practice, such as in machine learning, data mining tasks?


1 Answer 1


$R^2=1-\frac{SSE}{SST}$, where $SSE$ is the sum of squared error (residuals or deviations from the regression line) and $SST$ is the sum of squared deviations from the dependent's $Y$ mean.

$MSE=\frac{SSE}{n-m}$, where $n$ is the sample size and $m$ is the number of parameters in the model (including intercept, if any).

$R^2$ is a standardized measure of degree of predictedness, or fit, in the sample. $MSE$ is the estimate of variance of residuals, or non-fit, in the population. The two measures are clearly related, as seen in the most usual formula for adjusted $R^2$ (the estimate of $R^2$ for population):


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    $\begingroup$ I thought MSE is the avg of the errors, which means MSE = SSE/n, on what occasions do we use MSE=SSE/(n-m)? Please explain. Thanks $\endgroup$ Commented Jul 25, 2014 at 6:52
  • $\begingroup$ @SincoleBrans Please see en.wikipedia.org/wiki/Mean_squared_error, section "Regression". $\endgroup$
    – ttnphns
    Commented Jul 25, 2014 at 12:12
  • $\begingroup$ I'm a bit confused. The results in martin-thoma.com/regression show that a model can be good (compared to some other models) with R^2, but at the same time bad with MSE. Could you explain that? $\endgroup$ Commented Apr 17, 2018 at 7:03

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