Suppose that hockey players score 32% of penalty shots. Assume that three penalty shots are taken independently of one another. What is the probability that the team makes all three shots?
closed as off-topic by kjetil b halvorsen, Michael Chernick, Jakub Bartczuk, gung♦ Jun 27 '18 at 14:09
This question appears to be off-topic. The users who voted to close gave this specific reason:
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The probabilities of independent events are multiplicative. So the probability of events A and B occurring is P(A)*P(B). The same idea can be extended to more than two events. Imagine that the first player's shot is Event A, the second player's shot is Event B, and the third player's shot is Event C.