Suppose that hockey players score 32% of penalty shots. Assume that three penalty shots are taken independently of one another. What is the probability that the team makes all three shots?


closed as off-topic by kjetil b halvorsen, Michael Chernick, Jakub Bartczuk, gung Jun 27 '18 at 14:09

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  • 4
    $\begingroup$ Common goalie, among other things, renders that assumption invalid. Understanding that, and its consequences, is much more informative than a lame, pretend "real world" probability calculation. $\endgroup$ – Mark L. Stone Jun 26 '18 at 17:32
  • $\begingroup$ Please add the [self-study] tag & read its wiki. Then tell us what you understand thus far, what you've tried & where you're stuck. We'll provide hints to help you get unstuck. $\endgroup$ – gung Jun 27 '18 at 14:08
  • $\begingroup$ -1 because I believe this question should disappear (not much useful to people other than the original questioner). But to to still aid the questioner: check Bernoulli trials. en.wikipedia.org/wiki/Bernoulli_trial $\endgroup$ – Martijn Weterings Jun 29 '18 at 12:42

The probabilities of independent events are multiplicative. So the probability of events A and B occurring is P(A)*P(B). The same idea can be extended to more than two events. Imagine that the first player's shot is Event A, the second player's shot is Event B, and the third player's shot is Event C.

  • $\begingroup$ Please be cautious about providing answers to homework-style questions. Our policy (see here) is to provide hints only. The OP won't learn anything if you do it for them. $\endgroup$ – gung Jun 27 '18 at 14:10

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