# Variance of a poisson distribution

For a certain section of pine forest, the number Y of diseased trees per acre has a Poisson distribution with mean lambda=10. The disased trees are sprayed with an insecticide at a cost of 3 dollars per tree, plus a fixed overhead cost for equipment rental of 50 dollars. Letting C denote the total spraying cost for a randomly selected acre, find the expected value and variance for C.

Expected value is easy to find: 80

I'm stuck on Variance? Why is variance 90?

Because $C = 3Y+50$, and $var(C)=var(3Y+50)=9var(Y)=90$
• $E[C^2]=E[(3Y+50)^2]=E[9Y^2+300Y+2500]=9E[Y^2]+300E[Y]+2500$; since Possion variance is $\lambda = 10$, $E[Y^2] = var(Y) + E[Y]^2 = 110$. Substituting leaves us with $E[C^2] = 6490$. $E[C]^2 = 6400$, then $var(C) = 6490-6400=90$ – gunes Sep 9 '18 at 17:36