In the following slide I do not understand the definition of the term embedding.

In the third paragraph, it says it is a mapping from low-dim. to high-dim, but in the last paragraph it suggests that it is a map from high-dim. to low-dim. (which sounds quite natural to me).

Is the definition (third paragraph) incorrect? Manifold and embedding slide

  • $\begingroup$ I can't see your image/slide. $\endgroup$
    – gunes
    Sep 10, 2018 at 10:23
  • $\begingroup$ Weird, I see it. It can also be found here: i.stack.imgur.com/vT05O.png $\endgroup$
    – user_anon
    Sep 10, 2018 at 10:31
  • $\begingroup$ The last paragraph clearly states it is discussing situations where the method does not create a manifold and so no embedding either. There is no conflict $\endgroup$
    – ReneBt
    Sep 13, 2018 at 7:56
  • $\begingroup$ Perhaps you are right. I was disturbed by the word "but". I interpreted that sentence as: they create a manifold, but they do not create an embedding. $\endgroup$
    – user_anon
    Sep 13, 2018 at 8:14

2 Answers 2


Fortunately, I found on these slides an example:

The mapping $x = W z$ defines an embedding of an $m$-dimensional manifold in $p$-dimensional space

where $x$ is the original data. Moreover, now I understand why it is like this: the low-dim. space is embedded into the high-dim. space though an embedding (given a low-dim. vector, one applies the embedding to obtain the embedded version of the low-dim. vector into the high-dim. space).


While learning about a concept , never go with only a single source , try and cross validate with different texts , to confirm any hypothesis or definition.

This snippet itself is not comprehensive enough , and there should be more text supporting as to , what exactly embedding of manifold really is , and how well it should be understood to distinguish the so called "method" in this text.

Generally , embedding methods even in non-linear , or higher dimension can be visualized as regularization or decision trees.


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