0
$\begingroup$

Is there any way to compare the fit of quasi-Poission and negative binomial models? If so, can it be done in R?

$\endgroup$
6
  • 2
    $\begingroup$ What is your motivation for comparing these models? Have a look at Verhoef and Boveng, 2007, Ecology, 88(11). See also this post on comparing quasi-Poisson and negbin models (in R). $\endgroup$ – Jessica Burnett Nov 26 '18 at 22:36
  • 1
    $\begingroup$ @Jessica B It is precisely the issues highlighted by Verhoef & Boveng 2007 that motivate me to compare these models. Without some way to compare them (such as through a simulation) there is not a good way to know which one is the best choice for your data, but, critically, they are likely to yield different results. So - they are not equivalent, but it is not clear how to choose between the two of them without running some kind of simulation. I have seen the post by Elena Spark and Gavin Simpson, but did not find that it answered my question. It may be that the answer is simply "no". $\endgroup$ – JKO Nov 27 '18 at 16:01
  • $\begingroup$ In your OP you ask for an answer to, "is this possible in R," rather than "is this a good idea and if so, why?". Perhaps the answer to the latter is already posted in stats exchange? If you find something, please share as I am curious the answer(s). $\endgroup$ – Jessica Burnett Nov 27 '18 at 16:17
  • 1
    $\begingroup$ @Jessica Burnett It is not only a good idea to compare to find the best match for your data, but it is irresponsible not to (per Verhoef & Boveng 2007). Ironically, it seems (to me) like there is no good or clear way to do this. Hopefully, someone will correct me on that last point! $\endgroup$ – JKO Nov 27 '18 at 17:31
  • 1
    $\begingroup$ To be clear--my previous comment was to question whether your original question should include the term "in R"? $\endgroup$ – Jessica Burnett Nov 27 '18 at 18:03

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.