# Interpreting Regression Diagnostic Plots

I'm sorry if this is a broad question but can someone explain to me how to interpret these regression diagnostic plots? I understand the Normal Q-Q show's how normal the spread of the data is, but the other three I am confused by. For the Residuals vs Leverage, what does it mean for a point to be outside of the bounds? What does it mean if the red lines are parabolic and curved like in the first two? Why do we care about residuals, and what do they tell us? I've searched the web multiple times for some guide to interpret these and I can't get any straight forward answers. Any help is appreciated, thank you.

• Would you please post a link to the data? Dec 17, 2018 at 20:37
• Modern textbooks on multiple regression will cover all these plots in detail. We have fielded many questions about the top two plots, a few about scale-location plots, and only a small number about leverage. At any rate, searching our site will give you a good start.
– whuber
Dec 17, 2018 at 21:30

As mentioned above there are a fair few answers to assessing these kind of plots but it can't hurt to have all the answers in one place. I have created some data and code in R to illustrate my answer:

#Data creation
df <- data.frame(y = c(rep(1:100, 10)))
df$$x <- df$$y + rnorm(1000, sd = 5)


To begin with it is always good to plot your variables against one another. If you have just one predictor then something like:

 plot(y ~ x, data = df)


works well. If you have multiple predictors then you can use pairs(df). In this case the data looks like it has a positive linear association suggesting that an appropriate model is:

fit <- lm(y ~ x, data = df)


The second thing we look for in this plot (when assessing linear models - i.e. your response is normally distributed) is that the residuals are have roughly equal variance across the range of fitted values - I.e. the overall spread of the residuals is roughly equal across the range of fitted values. Put another way you don't have something like a trumpet or rugby ball shape, although there are other inappropriate shapes. This again means that the errors across your fitted line are not equal - some are underestimating while others are over-estimating which will throw out predictions and alters estimates/p-values. The plot should look something like this:

plot(fit, which = 1)


In my case the plot has some funny edges which are a result of how I created the data but it should serve to give an indication of what we are after.

The second plot (Normal Q-Q) checks that the errors are roughly normally distributed meaning that most of the residuals lie close to the line and a few far away. This has important implications for predictions again, but if you are only interested in p-values then it is less important as we can invoke the central limit theorem in most cases - some more reading on this here. Essentially we want the points to lie on the fitted line. If they don't it could be for any number of reasons. In your case it is likely due to the curvature that your model has missed but could also be fixed by a log-transformation of your response. The plot should look something like this:

plot(fit, which = 2)


Another way you can see this is using the normcheck function in the s20x library, which give a bit more intuitive output.

#install.packages("s20x")
library(s20x)
normcheck(fit)


The third plot (Scale-Location plot) shows much the same as the residual v.s. fitted plot but on a standardised scale. The residual v.s. fitted and scale-location plots can be used to assess heteroscedasticity (variance changing with fitted values) as well. The plot should look something like this:

plot(fit, which = 3)


This is also a better example of the kind of pattern we want to see in the first plot as it has lost the odd edges.

The final plot (residuals v.s. leverage) is a way of checking if any points are having undue influence over the line. The ordinary least squares equation, which is what linear models employ, tries to minimise the distance of the line from all the points. Points which are further from the line can sometimes have a greater influence over the plot - it's kind of like a sitting on the far end of a seesaw compared to sitting near the fulcrum. Typically the rule of thumb is that if a point has a cook's distance > 0.4 it has a large influence over the line and sometimes this might be criteria to remove it but this should never be done lightly. Your plot shows at least two points (22 and 50 - which corresponds to rows 22 and 50), along with their respective indexes, are having a large influence over your line. The indexes allow one to easily subset the points to have a look at them to see if they are wonky - sometimes it just comes down to an entry error. In your case I suspect that it is because the model is inappropriate rather than the data having anomalies. The plot should look something like this:

plot(fit, which = 4)


You can see in that last one that there are no red boundary lines like in the top right corner of yours - this is because non of my points come close to having high leverage. This can also be assessed using the s20x package in a more intuitive (I feel) way using the cooks20x function:

 cooks20x(fit)


Just look for points that are above 0.4 on the y-axis. The number displayed above each column is the row of the observation in the data frame.

I hope this helps!

• This was sooooooo helpful. Thank you for your straightforward and concise answer, I have a much better understanding of this now. Also, is the code you're using R or Python? Dec 18, 2018 at 5:59
• Also, are each of the points on these observations or variables? Dec 18, 2018 at 18:49
• Sorry should have clarified - my code was in R. Each of the points are individual observations meaning that they each correspond to a row in your data. - I have edited my answer to clarify. Glad it helped :) Dec 18, 2018 at 20:19