This isn't exactly a homework problem but rather a self-selected problem I'm doing to prepare for a midterm.
I can see from Wikipedia that it is an inverse gamma but I am unable to reach the posterior suggested by the parameter updates.
The Weibull as given on Wikipedia is:
$f(x_1,..,x_n|\lambda, k)=\frac{k}{\lambda}\left(\frac{x}{\lambda}\right)^{k-1}\text{exp}\left\{-\left(\frac{x}{\lambda}\right)^k\right\}$
Then
$L(\lambda|x_1,\dots, x_n)\propto \prod_x \lambda^{-k}\text{exp}\left\{-\frac{x^k}{\lambda^{k}}\right\}\\ =\lambda^{-nk}\text{exp}\left\{-\frac{\sum_x {x^k}}{\lambda^{k}}\right\}$
The inverse gamma prior is
$P(\lambda|\alpha,\beta)=\frac{\beta^\alpha}{\Gamma(\alpha)}\lambda^{-\alpha-1}\text{exp}\left\{-\frac{\beta}{\lambda}\right\}$
The posterior then is
$P(\lambda|x_1,\dots,x_n)\propto L(\lambda|x_1,\dots, x_n) P(\lambda|\alpha,\beta)\\ =\lambda^{-nk}\text{exp}\left\{-\sum_x {x^k}\lambda^{-k}\right\}\lambda^{-\alpha-1}\text{exp}\left\{-\frac{\beta}{\lambda}\right\}\\ =\lambda^{-nk-\alpha-1}\text{exp}\left\{-\frac{\sum_x {x^k}}{\lambda^{k}}-\frac{\beta}{\lambda}\right\}$
The problem that I am left with is to coerce an update for the $\beta$ hyperparameter that does not contain $\lambda$. The $\alpha$ also looks different from Wikipedia but I am going with explaining that as the difference between the posterior with observations and without, though honestly I'm confused about that as well. Wikipedia simply has the summation, $\sum_x {x^k}$ as the update for $\beta$ and $n$ for the update of $\alpha$ (not $nk$).
All of my efforts so far to coerce that $\beta$ update have failed.
