# Moving Average Representation of a Stationary Time Series

I was wondering if this equation is considered a Moving Average process of order 13? If so, does that mean that the coefficients at times t-2 to t-11 are 0? As they are clearly not present in this equation. (B is the Back shift operator and at is a white noise random variable)

Yes, this is a 13-th order MA process, i.e. MA(13). The order of the process/filter is defined as the largest exponent of the back shift operator. It doesn’t matter if the coefficients of other lower order components are zero or not. For example, $$x^2+1$$ would still be a second order polynomial, even though we don’t have $$x$$ inside the expression.