0
$\begingroup$

I found an article where they fit an ARIMA(p,d,q) model to a time series and then fit a GARCH(p,d,q) to the residual of the ARIMA (the parameters (p,d,q) are passed as the volatility model lags to the GARCH model and not as the mean model lags).

I know that the inconsistencies of doing them serially have been discussed here, here and in other posts. However, my question is if it is valid to reuse the lags of the ARIMA to fit the GARCH model. The traditional ARMA(p,q)-GARCH(r,s) does not do so and I could not find any reference supporting this.

$\endgroup$
  • $\begingroup$ @RichardHardy I meant o, but in this example, it was also zero. It was applied to the returns of the financial time series. $\endgroup$ – Pier-Olivier Marquis Mar 26 at 10:56
0
$\begingroup$

Generally, there is no reason to expect the model order for ARIMA to be the same as for GARCH, so would really question the use of the same orders in practice. It could be noted that sometimes very simple models such as ARMA(1,1)-GARCH(1,1) are used as rough approximations to the underlying autoregressive structure in the conditional mean and variance of, say, financial returns time series (e.g. these orders are the default in the ugarchspec function in rugarch package in R). But I doubt there is any general justification for other orders not equal to (1,1) or perhaps (1,0) or (0,1) (though I have shown here that GARCH($p$,0) does not make much sense for any $p>0$).

$\endgroup$
  • $\begingroup$ Thank you for this answer. I can't upvote it because my reputation is too low. $\endgroup$ – Pier-Olivier Marquis Mar 26 at 10:53
  • $\begingroup$ No problem at all. Thanks for your quick response. $\endgroup$ – Richard Hardy Mar 26 at 11:54

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.