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I understand how the simulation at Power calculation for likelihood ratio test can compute the alpha, using prop.test, and the power from a direct count of simulation values, for two Poisson distributed variables. I am interested in doing power analysis to determine the necessary number of samples, similar to using pwr.t.test(d = d, sig.level = 0.05, power = 0.8), except doing this between two samples from (suspected) Poisson distributions, and so thus not using t-tests.

With given distributions I could calculate alpha and the Power here, how would I determine a suitable n? I suppose one way is to write a loop that calculates power for increasing n until the power falls within the desired threshold, but that seems computationally intense.

What is the best way to approach this problem?

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  • $\begingroup$ What is the null hypothesis of your test ? $\endgroup$
    – Stéphane Laurent
    Oct 17, 2012 at 11:26
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    $\begingroup$ Why do you call this "retrospective" ? $\endgroup$
    – Peter Flom
    Oct 17, 2012 at 11:46
  • $\begingroup$ I am referring to retrospective, as in, I have taken 20 samples from each distribution and want to use that information to determine how many more samples I might need to take to determine if there was an effect. If the samples were normal, or Poisson with high lambda, I would calculate the d using the existing information, and then using a desired sig.level and power determine what n would be ideally. In this case, I want to create an equivalent test but for poisson distributions of low lambda. $\endgroup$
    – Matt
    Oct 17, 2012 at 15:38
  • $\begingroup$ The null hypothesis of my test here would be that lamda_1 = lambda_2, but what I am really interested in showing, in cases where I can't disprove the null hypothesis, is what number of samples I might need to take further in order to disprove the null hypothesis to my desired sig.level and power. (as in pwr.t.test) $\endgroup$
    – Matt
    Oct 17, 2012 at 15:41

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