I would like to make some short term forecasting using an AR(I)MA model. having the following daily time series, which is for the raw data: enter image description here

It seems to be like a white noise, based on the acf and pacf plots, which are the following: enter image description here

From my understanding from what I've read, a good choice would be AR(1) and MA(1).

Also, using ndiffs to find an appropriate number of the times to difference the series, I get 0 (which might be clear from the ACF graph). So, it seems I would need to create an ARIMA(1,0,1) model.

However, when I try to apply out-of-sample cross validation, it seems to be a straight line, i.e.

enter image description here

Question: How to interpret that? Probably I miss something or because of the lack of trend and seasonality I get these predictions?

P.S. If necessary, I can provide the code to generate the data and creating the corresponding graphs.

Edit: The model is the following one:

model = pm.auto_arima(
    start_p=1, start_q=1,

which actually produces an ARMA(1, 1) model.


Here is summary of the ARMA(1,1) model:

enter image description here

  • $\begingroup$ Can you edit your question to include the fitted model? $\endgroup$ Commented Jul 6, 2019 at 10:34
  • $\begingroup$ No, I meant the output. Specifically, the fitted AR and MA coefficients. $\endgroup$ Commented Jul 6, 2019 at 13:03
  • $\begingroup$ These are unusual data--certainly not any form of white noise. Would they be something like sales, net any returns? That would help explain the visible patterns, especially those of a variable that appears to be non-negative (and often zero) except during periods when it is non-positive. $\endgroup$
    – whuber
    Commented Jul 6, 2019 at 13:03
  • $\begingroup$ @StephanKolassa Is it ok now? $\endgroup$ Commented Jul 6, 2019 at 13:12
  • $\begingroup$ @whuber You are right. It's that kind of simulation. How could I go with this kind of data? $\endgroup$ Commented Jul 6, 2019 at 13:16

1 Answer 1


You have fitted an ARMA(1,1) model with an intercept (the "const") term, i.e.,

$$ Y_t - c = \phi_1(Y_{t-1}-c) + \theta_1\epsilon_{t-1} + \epsilon_t, $$


$$ \hat{c} = 5873.4432, \quad \hat{\phi_1}=-0.6770, \quad \hat{\theta_1}=0.5240 $$


$$ \epsilon_t\sim N(0,\sigma^2), \quad \hat{\sigma}=8807.627. $$

In forecasting the first step, say f\hat{\phi_1}^hor time $T+1$ if the last observation was at $T$, we use the last fitted innovation for the $\epsilon_{T}$ term, but we set the unknown $\epsilon_{T+1}$ to its expected value, which is zero. So our first forecast is

$$ \hat{Y}_{T+1} = \hat{\phi}_1(Y_T-c)+\hat{\theta}_t\hat{\epsilon}_T+c. $$

Further forecasts iterate this out:

$$ \hat{Y}_{T+h} = \hat{\phi}_1(\hat{Y}_{T+h-1}-c)+c \to \hat{\phi_1}^h(Y_T-c)+c. $$

This is not a flat line, but since $\hat{\phi_1}^h\to 0$, the forecasts converge to the constant $c$. For all intents and purposes, the forecasts will get flatter and flatter.

Why does this look flat immediately? The key insight is that your innovations have a high noise: $\hat{\sigma}=8807.627$. That means that the observations show much more variation than the fitted and extrapolated mean.

As a sanity check, here is a simulated series with a forecast, using your fitted model (note the tiny wiggle at the beginning of the forecast!):

ARIMA simulation

We see that the simulated observations and the forecast are roughly in the correct ballpark. R code (sorry, I don't speak Python fluently enough):

nn <- 100
starting_observation <- 6000
const <- 5873.4432
sd_innovations <- 8807.627
ar1 <- -0.6770
ma1 <- 0.5240

starting_innovation <- rnorm(1,0,sd_innovations)

# simulate:
observations <- c(starting_observation,rep(NA,nn-1))
innovations <- c(starting_innovation,rep(NA,nn-1))

for ( ii in 2:nn ) {
    innovations[ii] <- rnorm(1,0,sd_innovations)
    observations[ii] <- ar1*(observations[ii-1]-const)+ma1*innovations[ii]+const

forecasts <- (starting_observation-const)*ar1^(1:nn)+const


Two observations:

  1. There is some ambiguity on the semantics of the MA parameter; the parameter in the formulas above may need to be switched. But this doesn't have an impact on the argument.

  2. As whuber writes, these are certainly not ARIMA data. There is an obvious overabundance of zeros. (Which is responsible for the simulation having a smaller vertical range than your data.) If I understand you correctly, these are sales data, net of returns (the negative values). If you want to forecast these, your first step should really be to understand your data better. You seem to have returns infrequently, but when returns do happen, they happen in thousands. Understanding what happens here should really be your first priority. (And even then, you may not be able to do better than your ARMA(1,1) with intercept model, or for that matter, a simple mean.)

  • $\begingroup$ Great, thanks for the answer! Indeed, there is roughly a 60% of zeros in there. I tried removing the zeros, but it doesn't make any real difference. So, I guess that's the best I can do! $\endgroup$ Commented Jul 6, 2019 at 15:21

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