AIC and BIC values by auto.arima and manual ARIMA A time series of yearly data, I want to compare the AIC and BIC values by auto.arima and manual ARIMA.
library(forecast)

drink <- c(188,301,451,504,630,855,883,1078,1099,1008,1050,1058)

drink_ts <- ts(drink, frequency = 1, start=c(1950))

auto.arima(drink_ts)

# Series: drink_ts
# ARIMA(0,1,0) with drift 
# Coefficients:
#         drift
#       79.0909
# s.e.  26.5245

# sigma^2 estimated as 8513:  log likelihood=-64.86
# AIC=133.71   AICc=135.21   BIC=134.51

I want to replicate it, so do a manual with same ARIMA(0,1,0):
drink.fit <- arima(drink_ts, order = c(0,1,0))
drink.fit

To get the AIC and BIC values:
AIC(drink.fit)
BIC = AIC(drink.fit,k = log(length(drink_ts)))
BIC

# AIC: 138.7121
# BIC: 138.2272

The AIC and BIC values by auto.arima and manual ARIMA are slightly different. 
Does it matter? Am I missing anything in the manual ARIMA? 
(by the way, if there’s a direct way to get the AIC and BIC from the manual ARIMA)
Thank you.
 A: You are missing one thing. Note that auto.arima() fits an ARIMA(0,1,0) model with drift. This is the following model:
$$ (1-B)(y_t-\mu t) = e_t, $$
or after rearranging,
$$ y_t = y_{t-1}+\mu+e_t. $$
The estimated value of $\mu$ is the 79.0909 you get.
So if you wanted to reconstruct your auto.arima() results, you would first have to "correct" your time series drink_ts by this drift term. Unfortunately, it's not clear how the t parameter runs - does it start from 1950 (being the first year in your series), or from 1 (which sounds more reasonable - but would yield a nonzero intercept).
I played around a bit, but couldn't fully reconstruct your AIC values. Part of the problem is of course accounting for the degree of freedom expended in estimating the drift parameter, similarly whether to allow a mean or constrain it, and finally likely slight differences in estimating methods between arima() and auto.arima().
In general, I would trust auto.arima() more than a hand-crafted call to arima. (And regarding your parenthetical question, you can extract the AIC by arima(drink_ts)$aic, but I don't know of a way to get the BIC, or the AICc.)
If your question is still open, maybe you could either ask a new question that avoids the drift complications (possibly linking the two questions), or edit to explain why you are trying to do what you are trying to do?
