This is continuation of my problem
Calculate variance of sum random variables
Suppose random variable $X$ takes 3 values $1, 2, 3$ with probability $\frac{1}{2}$, $\frac{1}{3}$ and $\frac{1}{6}$. Sample 1000 times from $X$ independently and do the following operations. Take a number $T=0$. If 1 comes, add 0.18 with $T$, if 2 comes add 0.05 with $T$ if 3 comes add -0.29 with $T$. Then expected value of $T$ will be 58.33 and variance will be 27.65. Now I want to find the probability $T<50$. For this I tried to use central limit theorem namely I approximated the distribution by Normal $N(58.33,27.65)$. Then integrate the density function of this normal distribution from -infinity to 50 to get the probability. Can we use better approximation than this? Since we know higher moments of $T$, can we somehow use these values?