# How to determine which category is most likely given an observation with a set of characteristics

I have a question concerning the data analysis methods to use for a specific situation. Here is the situation:

There is a dataset from an e-commerce site about its customers' purchases with 875 observations total. Each observation consists of 5 values. Scales of value measurement available for each observation (for each customer) are summarised in the following:

1. Package Type (Nominal): Type 1, Type 2, Type 3
2. Sex (Nominal): Male, Female
3. Age Group (Ordinal): NULL, Younger than 20, 20-25, Older than 25
4. Location (Nominal Scale): NULL, Region 1, Region 2
5. Order Count (Ratio Scale): Integers

NULL represents missing data.

The task is to identify which Package Type is preferred by which client type, composed of Sex, Age Group, Location and Order Count. Put another way: what is the Package Type is most likely given the set of characteristics, consisting of Sex, Age Group, Location and Order Count?

What am I asking for is not a ready solution for this problem - this just wouldn't be so interesting :). I want you to head me towards the methodology that would be used in answering this question. What branch of Statistics might handle this problem? Maybe you could advise me some good classic book covering the subject or the forum thread?

• A couple of small notes about the scales of measurement that you list: (1) Only the scale of the response variable is of primary importance; (2) The concept of measurement scales is largely overrated, IMHO; (3) I wouldn't call a count variable (i.e., your #5) a ratio scale variable--it's sort of true, but not really the right way to think about it. – gung Nov 12 '12 at 23:24
• No time for a proper answer but my proto-answer on key words is classification analysis as a general branch; and multinomial regression as one particular technique that would be useful. – Peter Ellis Nov 12 '12 at 23:34
• Great, thank you all for the expanded answers! This is a great place there. I'll try everything, thank you again. – Anton Ivanov Nov 17 '12 at 16:07