This is a very simple question, but I want to make sure I am doing it correctly.
I have the pdf from a Pareto distribution:
$$f(x) = 160 x^{-6}, \ \ 2 \leq x < \infty$$
and want to obtain the cdf
$$F(x) = \int_{- \infty}^x f(t) \mathrm{d}t$$
In this case, is it the same if I substitue the lower bound of the integral to $2$ since the pdf is specifically defined for $x \in [2, \infty)$ such that $F(x) = -32x^{-5} + 1$?