1
$\begingroup$

I am trying to solve the ridge regression problem given by

$D_{s} = min_{D_{s}} \hspace{2mm} || X_{s} - D_{s}Y_{s}||_F^{2} + \lambda \hspace{2mm} ||D_{s}||_{F}^{2} \hspace{10mm} s.t. \hspace{5mm} ||d_{i}||_{2}^{2} \leq 1$

What extra information is this $||d_{i}||_{2}^{2} \leq 1$ giving and how to incorporate this in the objective function.

Actually, I tried to incorporate $||d_{i}||_{2}^{2} \leq 1$ by writing it as $||D_{s}||_{F}^{2} \leq 1$. Am I correct ?

$D_{s}$ is the matrix that need to be learnt.

$\endgroup$
1
  • 2
    $\begingroup$ Could you clarify your notation and the type of problem you are addressing? It looks like a multivariate regression model where you have more than one dependent variable for each observation. However using the standard notation of $Y$ for the dependent variables and $X$ for the independent variables, then your sum of squared errors would be $\|Y-XD\|$ instead of $\|X-YD\|$. Also could you clarify if $d_i$ is a row or column of $D_s$? Finally, presumably the constraint is supposed to hold for all $i$. $\endgroup$
    – josliber
    Commented Mar 4, 2020 at 14:29

1 Answer 1

2
$\begingroup$

It looks like you might be confusing the Penalized and Lagrangian forms of ridge regression, and trying to do both at once. See e.g. One-to-one correspondence between penalty parameters of equivalent formulations of penalised regression methods

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.