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With $X$ being the design matrix, calculate the diagonal elements of the matrix $(X^TX)^{-1}$ using only the R output.

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I found the diagonal elements to be $$\frac{1}{n SSX} \bigg[n,\sum X_{i1}^2, \sum X_{i2}^2 \bigg]$$ but I don´t see any way of calculating this based on the R output.

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Hint: Find the formula for the standard errors of the coefficient estimators. Notice also that these standard errors are given to you in the output.

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  • $\begingroup$ So $Var(\hat{\beta}) = \sigma^2 (X^TX)^{-1}$ But I don't see how to extract diagonal elements this way? Also, isn't $\hat{\beta}$ a $px1$ matrix, while $(X^TX)^{-1}$ is an $nxn$ matrix? $\endgroup$
    – Pame
    Apr 8, 2020 at 14:10
  • $\begingroup$ It's a $p \times p$ matrix $\endgroup$
    – JTH
    Apr 8, 2020 at 14:24
  • $\begingroup$ Still doesen´t make much sense if the left hand side is a $px1$ matrix and the right hand side a $pxp$ matrix. $\endgroup$
    – Pame
    Apr 9, 2020 at 7:11
  • $\begingroup$ Please have a look here. $\endgroup$
    – Ben
    Apr 9, 2020 at 7:18
  • $\begingroup$ Okay, so then the diagonal elements of $(X^TX)^{-1}$ are given by $\frac{Var(\beta_i)}{\sigma^2}$ ? $\endgroup$
    – Pame
    Apr 9, 2020 at 9:01

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