In the common setup, you perform a test involving a test statistic, say $T$, and obtain a p-value, say $a$. Given that you have observed a value $t$ of the test statistic, the relation between $T$ and $a$ often is something like
$$
a = P(T > t\ |\ H_0) \quad \text{or} \quad a = P(|T| > t\ |\ H_0) \quad \text{or} \quad a = P(T < t\ |\ H_0),
$$
where $H_0$ is the null. The way of defining $a$ depends on the meaning of your statistic $T$, as it represents the probability of observing $T = t$ or worse given that the null hypothesis is true. It depends of what you judge to be a bad value of $T$ (evidence against $H_0$).
In your case, $T$ could be the difference in drug effect (bigger is better), i.e. $T = E_B - E_A$ and your p-value could then be $a = P(T > t)$. Observing a big value of $T$ gives more evidence in favor of the alternative hypothesis, that is against $H_0$.
That being said, if $a$ is the probability of observing what you have observed (or worse) during the experiment, obtaining a small value of $a$ means that what you have observed is unlikely to happen if $H_0$ is true, and so there is not much evidence for $H_0$. Thus, you usually reject $H_0$ in this case. The role of $a$ is to quantify how unlikely it is to observe $T=t$.
Now fix $t$ to be the value of the test statistic computed on the original experiement and say it corresponds to a p-value of $a=0.01$. Assuming that $H_0$ is indeed true, what would happen if you were to repeat this experiment over and over again? If $a$ is the probability of observing $T>t$, then this means you would indeed observe $T>t$ on approximately $0.01\times 100 = 1\%$ of you experiments. So even if $H_0$ is true, there is still a slight chance that you observe a small p-value. This "slight chance" is exactly what you specify as your significance level: you specify what it means for a p-value to be small (less than $5\%$ for example).
All this to say, it is intuitive to think of the significance level $\alpha$ as follows : if $H_0$ was true and you were to repeat the experiment many times, you would expect to (wrongly) reject the null hypothesis $(\alpha\times 100)\%$ of the times.