0
$\begingroup$

Can we verify if $E(X^2)$ also exist, provided that E(X) exists?

Thanks.

Improve this question
$\endgroup$
1

1 Answer 1

Reset to default
0
$\begingroup$

No, only the other direction is valid due to Jensen's inequality.

Improve this answer
$\endgroup$
0

Not the answer you're looking for? Browse other questions tagged or ask your own question.