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Suppose you have a sequence of random variables $ \left\lbrace X_{i}\right\rbrace_{i=1,...,n}$ which converges in probability to a random variable $X$, shown by $ X_n \ \xrightarrow{p}\ X$ as n goes to $\infty$.

$$\lim_{n\rightarrow\infty} P(|X_n-X|>\varepsilon) = 0$$

Now, suppose we can furteher obtain a sequence of random variables for each n $ \left\lbrace X_{j,n}\right\rbrace_{j=1,...,m}$ such that $ X_{m,n} \ \xrightarrow{p}\ X_n$ as m goes to $\infty$.

$$\lim_{m\rightarrow\infty} P(|X_{m,n}-X_{n}|>\varepsilon) = 0$$

My question is, may I define $ X_{m,n} \ \xrightarrow{p}\ X$ as both m and n go to $\infty$ at the same time (double limit)?

$$ \lim \limits_{\substack{% m \to \infty\\ n \to \infty}} P(|X_{m,n}-X|>\varepsilon) = 0$$

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Maybe I found the solution in the following Appendix on DOUBLE ASYMPTOTICS

See equation C.9

Therefore it is sufficient that $m/n$ (or $n/m$) converges to a constant to ensure the double asymptotic convergence.

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