Assume a bag that contains 3 balls. Each ball is either red or blue. The number of blue balls, call it θ, might be 0, 1, 2, or 3. Choose 4 balls at random from the bag with replacement. define the i.i.d. random variables $X_1$, $X_2$, $X_3$, and $X_4$ as follows
\begin{equation} X_i = \left\{ \begin{array}{l l} 1 & \qquad \text{if the $i$th chosen ball is blue} \\ & \qquad \\ 0 & \qquad \text{if the $i$th chosen ball is red} \end{array} \right. \end{equation}
Given $X_i \sim Bernoulli(\frac{\theta}{3})$. I understand $(x_1, x_2, x_3, x_4)=(1,0,1,1)$ means there are 4 observed values, blue for the 1st observation, red for the 2nd observation, and blue for both 3rd and 4th observation.
Given $X_i \sim Binomial(3, \theta)$ What could $(x_1,x_2,x_3,x_4)=(1,3,2,2)$ mean?
The question comes from Example 8.8 in this statistics tutorial