$Y$ is equal to the sum of $n$ independent identically distributed Gaussian distribution variables, where $n$ is Poisson distribution $Y$ is equal to the sum of $n$ independent identically distributed Gaussian distribution variables, where $n$ is Poisson distribution. If $Y$ is approximated to Gaussian distribution, what is its variance?$$Y = \sum\limits_{i = 0}^n {{x_i}}, $$ where ${x_i} \sim N\left( {0,{\sigma ^2}} \right)$, $n \sim {\rm{Pois}}\left( \lambda  \right)$.
If we directly calculate the variance of $Y$ by summation, the variance is $n{\sigma ^2}$. When $\lambda$ is large, $n{\sigma ^2}$ is a Gaussian distribution variable. That is, $Y$ can be regarded as a Gaussian distribution with ${\sigma ^2_Y}$ as Gaussian r.v. But I can't find any information about this composite distribution.
 A: You can compute first the distribution of $Y$ conditional on the value of $n$. It is a normal distribution
$$Y_n \sim N(0,n\sigma^2)$$
Compound mixture distribution
And the distribution of $Y$ unconditional on $n$ is like a compound distribution or mixture distribution.
$$Y \sim N(0, n\sigma^2) \qquad \text{where $n \sim Pois(\lambda)$}$$ ​
To compute the raw moments you can take the sum of the individual components
$$E(Y) = \sum p(n) E(Y_n) = 0$$
$$E(Y^2) = \sum p(n) E(Y_n^2) = \sum p(n)  n \sigma^2 = \bar{n} \sigma^2 = \lambda \sigma^2$$
And for the variance
$$Var(Y) = E(Y^2) - E(Y)^2 = \lambda \sigma^2$$
Product distribution
You can view this also as a product distribution
$$Y = \sqrt{N}X \qquad \text{where $N \sim Pois(\lambda)$ and $X\sim N(0,\sigma^2)$}$$
And then use this rule for the variance of a product of variables
$$Var(XY) = (\sigma_X^2 + \mu_X^2) (\sigma_Y^2 + \mu_Y^2) - \mu_X^2\mu_Y^2$$
We have $\mu_X = 0$ and
$$Var(XY) = \sigma_X^2 (\sigma_Y^2 + \mu_Y^2)$$
note that $(\sigma_Y^2 + \mu_Y^2)$ is equal to the raw moment $E(Y^2)$, and in our case $Y$ is the square root of a Poisson distributed variable so $Y^2$ is distributed as a Poisson distributed variable and it's expectation is $\lambda$.
$$Var(X\sqrt{N}) = \lambda\sigma^2$$
