1
$\begingroup$

I've two independent and uniform random variables $Z_1,Z_2 \in \lbrace 1,2,3,4 \rbrace$. Can you tell me why the following equality is correct please?

$$ P(Z_1+Z_2=2,Z_1=1,Z_2=1)=P(Z_1=1,Z_2=1) $$

$\endgroup$
4
  • $\begingroup$ The LHS is vague, what does it mean? $\endgroup$
    – gunes
    Commented Jan 8, 2022 at 8:58
  • $\begingroup$ Hello @gunes do you mean that the notation is vague? $\endgroup$ Commented Jan 8, 2022 at 8:59
  • $\begingroup$ Yes @GennaroArguzzi $\endgroup$
    – gunes
    Commented Jan 8, 2022 at 8:59
  • $\begingroup$ @gunes sorry there was a typo $\endgroup$ Commented Jan 8, 2022 at 9:00

1 Answer 1

1
$\begingroup$

This holds even if the variables are neither independent nor uniform because the event $Z_1+Z_2=2$ does not add anything when the RVs are both $1$.

$\endgroup$
3
  • $\begingroup$ Yes, similar to that. $\endgroup$
    – gunes
    Commented Jan 8, 2022 at 9:04
  • $\begingroup$ is it like writing the same event twice? $\endgroup$ Commented Jan 8, 2022 at 9:04
  • $\begingroup$ thank you very much $\endgroup$ Commented Jan 8, 2022 at 9:04

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.