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I want to find confidence intervals for my scenario and I see this sentence in many research papers related to my work. " Confidence interval of less than 1% of the average value"? What does it mean? You can also explain this with the example given below.

E.g. Say for x=100, y= 0.01. This 0.01 is obtained as an average of running the code 10 times for x=100. I will use those 10 values to find the confidence interval at this x=100 point. Hope this is the right way to compute the interval.

Context as asked: I am plotting some blocking value (y-axis) against traffic load (x-axis). X-axis values from 100,200, upto (say) 800. And y-axis values are of the form 0.006 or 0.01 or 0.2 and so on. I run the code to generate y value for the given x and I do this 10 times and take the average. So, each blocking value point vs a given x is an average of 10 times. I want to plot confidence intervals for each x point. So I assume I have to use those 10 values as the sample values to calculate the interval. Is it correct? If so, then I want to know the meaning of the statement I asked at the top in this context.

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    $\begingroup$ It would be really helpful if you included some context or examples. $\endgroup$ Jan 14 at 18:51
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    $\begingroup$ @MattKrause I have added the context. Please re-open. I agree that the context wasn't detailed but don't know why it was downvoted to indicate no research effort. The example I gave itself is self-made (research effort) in order to let people find it easy to explain my first statement. Hope it fits the criteria for reopening now. $\endgroup$ Jan 14 at 21:17
  • $\begingroup$ I appreciate your effort. However, the quoted statement, because it is just a fragment, makes no sense in English, which is one reason we are looking for context and clarification. $\endgroup$
    – whuber
    Jan 14 at 21:20
  • $\begingroup$ @whuber I understand. Thanks. I hope now it is understandable and someone is able to throw light. $\endgroup$ Jan 14 at 21:21
  • $\begingroup$ I won't be able to understand it without further explanation. $\endgroup$
    – whuber
    Jan 14 at 21:22

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