Consider a simple regression model, $y=\beta^Tx+\epsilon$, say using the cars
dataset. We get the following summary:
> summary(lm(dist~speed,cars))
Call:
lm(formula = dist ~ speed, data = cars)
Residuals:
Min 1Q Median 3Q Max
-29.069 -9.525 -2.272 9.215 43.201
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) -17.5791 6.7584 -2.601 0.0123 *
speed 3.9324 0.4155 9.464 1.49e-12 ***
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
Residual standard error: 15.38 on 48 degrees of freedom
Multiple R-squared: 0.6511, Adjusted R-squared: 0.6438
F-statistic: 89.57 on 1 and 48 DF, p-value: 1.49e-12
The Estimate
is the value of $\hat\beta_j$, obtained using OLS: $\hat\beta=(X^TX)^{-1}X^Ty$;
Residual standard error
is $s=\sqrt{\frac{SSE}{n-p}}=\sqrt{\frac{\sum_{i=1}^n{(y_i-\hat{y}_i)^2}}{n-p}}$;
Std. Error
is $s_j=s\sqrt{(X^TX)^{-1}_{jj}}$ and t value
is $t_j=\frac{\hat\beta_j}{s_j}=\frac{\sqrt{n-p}\hat{\beta}_j}{\sqrt{SSE(X^TX)^{-1}_{jj}}}$. $\hat\beta_j$ has a normal distribution, $s^2\sim\chi^2_{n-p}$ and $t_j\sim t_{n-p}$ (central $t$ under $H_0$: $\beta_j=0$). Up to here it's a well-known collection of results.
Now, consider a different regression problem: $y\sim\mathcal{N}(2x+1,1)$. We generate the data and build the regression model for different sample sizes:
n <- 10*(1:1000)
for(i in n){
set.seed(i)
x <- rnorm(i)
set.seed(i+1)
y <- rnorm(i, 1+2*x)
dat <- data.frame(x,y)
lr <- lm(y~., dat)
ct <- summary(lr)$coef
}
We can see that $\hat\beta_j$ is a consistent estimator of $\beta$:
On the other hand, $t_j$ diverge with rate $\sqrt{n}$:
but $t_j/\sqrt{n}$ is a consistent estimator of something:
My questions are the following:
What should be the expected value of $t_j$? naturally this should be 0 (as per centralized t distribution) but I'm doubting everything right now.
What can I say about the value of $t_j/\sqrt{n}$? Does it have any particular meaning?
What can I say about the distribution of $t_j/\sqrt{n}$? Properties of the ratio distribution provide us that if $A\sim N,B\sim\chi^2_k$ then $\frac{A}{\sqrt{B/k}}$ is t-distributed, is there anything about $\frac{A}{\sqrt{B}}$?