# Fitting data to gamma distribution to find score which corresponds to pvalue < 0.05?

I have data of size 116.667 rows defined as:

iD  Signal
chr17.3620  0.5741552
chr1.7341   0.5680284
chr7.3937   0.5479430
chr17.3890  0.5402434
chr12.3200  0.5298978
chr17.7227  0.5298536


As it is difficult to show results with all the data, because I have no reputation enough to upload images I made my post with the first 200 rows.

Summary:

• Min. = 0.3693
• 1st Quartile = 0.3847
• Median = 0.4039
• Mean = 0.4199
• 3rd Quartile = 0.4413
• Max. = 0.5742

Also I tried some exploratory analysis to see which kind of distribution follows this data (i.e. plot(density(t)) and qqnorm(t); qqline(t,col=2)). According to preliminary results, I would say that this data apparently follows a gamma distribution.

Here I put the first 200 signal values:

A <- structure(list(V1 = c(0.5741552,0.5680284,0.5479430,0.5402434,0.5298978,0.5298536,0.5282417,
0.5165426,0.5131503,0.5129329,0.5105448,0.5104201,0.5095860,0.5090263,
0.5061467,0.4972821,0.4959428,0.4953381,0.4920510,0.4915160,0.4868505,
0.4843749,0.4825519,0.4823313,0.4809742,0.4788553,0.4775991,0.4770962,
0.4745947,0.4743952,0.4727112,0.4718017,0.4714738,0.4674141,0.4670385,
0.4648104,0.4633502,0.4616054,0.4615068,0.4614247,0.4613338,0.4597812,
0.4551755,0.4535067,0.4528133,0.4508228,0.4494993,0.4494936,0.4442789,
0.4413460,0.4412279,0.4402557,0.4392294,0.4385639,0.4385187,0.4361337,
0.4344499,0.4342413,0.4342331,0.4338879,0.4337806,0.4336820,0.4329372,
0.4325534,0.4323201,0.4312287,0.4292037,0.4281761,0.4279843,0.4279774,
0.4252035,0.4243487,0.4228516,0.4226953,0.4218263,0.4214821,0.4212546,
0.4210894,0.4206089,0.4204235,0.4193896,0.4168915,0.4164699,0.4152126,
0.4127455,0.4126053,0.4113571,0.4105654,0.4099753,0.4088188,0.4085093,
0.4075957,0.4074018,0.4072499,0.4072114,0.4067329,0.4065400,0.4052757,
0.4044982,0.4040699,0.4036509,0.4033471,0.4031712,0.4026698,0.4017872,
0.4011538,0.4011325,0.4011320,0.4008897,0.4006470,0.4003469,0.3996736,
0.3992583,0.3991979,0.3990366,0.3989118,0.3983172,0.3980860,0.3978592,
0.3977522,0.3965371,0.3963045,0.3957640,0.3954328,0.3950159,0.3935825,
0.3934975,0.3932916,0.3931091,0.3929565,0.3922829,0.3919779,0.3919713,
0.3914740,0.3910446,0.3909540,0.3890607,0.3890550,0.3876478,0.3875172,
0.3873815,0.3872299,0.3870533,0.3858995,0.3858361,0.3855984,0.3854444,
0.3852595,0.3849558,0.3847531,0.3844442,0.3842814,0.3831377,0.3822418,
0.3817666,0.3805661,0.3803090,0.3802035,0.3800845,0.3800580,0.3799694,
0.3795814,0.3794039,0.3792874,0.3788970,0.3787295,0.3785160,0.3782523,
0.3782439,0.3779547,0.3778596,0.3777452,0.3770986,0.3767652,0.3767104,
0.3765786,0.3760886,0.3760124,0.3753271,0.3750943,0.3749116,0.3744146,
0.3743998,0.3730250,0.3729932,0.3727007,0.3726170,0.3722539,0.3721743,
0.3721055,0.3720965,0.3718959,0.3714824,0.3711862,0.3709115,0.3708262,
0.3706647,0.3701728,0.3697490,0.3692868)))

t<-as.matrix(A$V1)  My questions are: 1.- How can I fit my data to a gamma distribution? 2.- Is there any way to determine, according to the model fitting, which signal value corresponds to p-value < 0.05? Thanks for your help! PD 1: I accept suggestions in order to edit as this is my first post in the community! PD 2 : I've been trying all of this using R • 1. One simple way to fit a gamma distribution to the data is the method of moments: the gamma distribution with parameters$(\alpha, \beta)$has mean$\frac\alpha\beta$and variance$\frac\alpha{\beta^2}$. You can use sample estimates of the mean and variance and some algebra to solve for the parameters of the model. Naturally, more advanced methods exist. But with the large number of observations, this should be a good starting point. 2. I'm uncertain what your second question means. Are you looking for the score which divides the smallest 95% of your data from the largest 5%? – Sycorax May 6, 2013 at 13:27 • Why use a fitted model? With over 100K values, it's possible that any fit will disagree significantly with the data. What's the matter with just finding the$.05$(or$.95$) quantiles of the data (presuming that's what you mean by "p-value," which otherwise makes no sense in this context)? – whuber May 6, 2013 at 14:13 ## 1 Answer You can try to use fitdistrplus and logspline packages to check which distribution could help you to explain your data. Basicly you have to provide the variable (i.e V1) in your data frame (df) and run the descdist() function: descdist(df$V1, discrete = FALSE, boot = 1000)

Next, you can try and fit a couple of distributions like gamma, exponential ...etc, like this:

fit.gamma <- fitdist(df$V1, "gamma", method = "mle") plot(fit.gamma) summary(fit.gamma) And finally you can merge all together (i.e fit.gamma, fit.exp, fit.beta) in order to get the Kolmogorov-Smirnov among other tests: goodness <- gofstat(list(fit.gamma, fit.beta, fit.exp), fitnames = c("gamma", "beta", "exp")) goodness$chisqpvalue