User2974951's is correct and to the point.
For further readers that are still wondering where that 0 comes from and why it doesn't make sense to look at the '-14', which is a common mistake for novices, here is why:
First of all, remember what is initially the goal and what is going on. In this example, they want to test if a certain difference (let's call it $\Delta$) is significantly different from 0 or not. (i.e.: $H_0: \Delta = 0$ & $H_a: \Delta \neq 0$).
Next, remember how a confidence interval is constructed, i.e.: point estimate $\pm$ error margin, or in this case in terms of formula, one often uses: $\Delta \pm CritVal \times se(\Delta)$, where the critical value is for example 1.96 in the case of a normal approximation.
Now in this example: $\Delta$ = -14, meaning that to construct the confidence interval, you would substract some error margin/uncertainty from this -14 and add some. This will of course create an interval that includes -14 already since you added and substracted from -14 to make the interval in the first place! Therefore it does not make sense to check if -14 is in there to prove significance, since it will by construction of the interval automatically be in there. However, since you want to test if the difference $\Delta$ is different from 0, you rather check that 0 is in the interval or not. Similarly, if you want to check, if it is also significantly different from 10, you can set up an analogue hypothesis and check if 10 is in the interval or not.