I am wondering what the exact relationship between partial $R^2$ and coefficients in a linear model is and whether I should use only one or both to illustrate the importance and influence of factors.

As far as I know, with summary I get estimates of the coefficients, and with anova the sum of squares for each factor - the proportion of the sum of squares of one factor divided by the sum of the sum of squares plus residuals is partial $R^2$ (the following code is in R).


lm(formula = education ~ income + young + urban, data = Anscombe)

    Min      1Q  Median      3Q     Max 
-60.240 -15.738  -1.156  15.883  51.380 

              Estimate Std. Error t value Pr(>|t|)    
(Intercept) -2.868e+02  6.492e+01  -4.418 5.82e-05 ***
income       8.065e-02  9.299e-03   8.674 2.56e-11 ***
young        8.173e-01  1.598e-01   5.115 5.69e-06 ***
urban       -1.058e-01  3.428e-02  -3.086  0.00339 ** 
Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Residual standard error: 26.69 on 47 degrees of freedom
Multiple R-squared:  0.6896,    Adjusted R-squared:  0.6698 
F-statistic: 34.81 on 3 and 47 DF,  p-value: 5.337e-12

Analysis of Variance Table

Response: education
          Df Sum Sq Mean Sq F value    Pr(>F)    
income     1  48087   48087 67.4869 1.219e-10 ***
young      1  19537   19537 27.4192 3.767e-06 ***
urban      1   6787    6787  9.5255  0.003393 ** 
Residuals 47  33489     713                      
Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

The size of the coefficients for 'young' (0.8) and 'urban' (-0.1, about 1/8 of the former, ignoring '-') does not match the explained variance ('young' ~19500 and 'urban' ~6790, i.e. around 1/3).

So I thought I would need to scale my data because I assumed that if a factor's range is much wider than another factor's range their coefficients would be hard to compare:


lm(formula = education ~ income + young + urban, data = Anscombe.sc)

     Min       1Q   Median       3Q      Max 
-1.29675 -0.33879 -0.02489  0.34191  1.10602 

              Estimate Std. Error t value Pr(>|t|)    
(Intercept)  2.084e-16  8.046e-02   0.000  1.00000    
income       9.723e-01  1.121e-01   8.674 2.56e-11 ***
young        4.216e-01  8.242e-02   5.115 5.69e-06 ***
urban       -3.447e-01  1.117e-01  -3.086  0.00339 ** 
Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Residual standard error: 0.5746 on 47 degrees of freedom
Multiple R-squared:  0.6896,    Adjusted R-squared:  0.6698 
F-statistic: 34.81 on 3 and 47 DF,  p-value: 5.337e-12

Analysis of Variance Table

Response: education
          Df  Sum Sq Mean Sq F value    Pr(>F)    
income     1 22.2830 22.2830 67.4869 1.219e-10 ***
young      1  9.0533  9.0533 27.4192 3.767e-06 ***
urban      1  3.1451  3.1451  9.5255  0.003393 ** 
Residuals 47 15.5186  0.3302                      
Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1    

But that doesn't really make a difference, partial $R^2$ and the size of the coefficients (these are now standardized coefficients) still do not match:

# income: partial R2 0.446, Coeff 0.97
# young:  partial R2 0.182, Coeff 0.42
# urban:  partial R2 0.062, Coeff -0.34

So is it fair to say that 'young' explains three times as much variance as 'urban' because partial $R^2$ for 'young' is three times that of 'urban'? Why is the coefficient of 'young' then not three times that of 'urban' (ignoring the sign)?

I suppose the answer for this question will then also tell me the answer to my initial query: Should I use partial $R^2$ or coefficients to illustrate the relative importance of factors? (Ignoring direction of influence - sign - for the time being.)


Partial eta-squared appears to be another name for what I called partial $R^2$. etasq {heplots} is a useful function that produces similar results:

          Partial eta^2
income        0.6154918
young         0.3576083
urban         0.1685162
Residuals            NA
  • $\begingroup$ What are you trying to do or show exactly? The estimated influence? The significance? $\endgroup$ – IMA Jul 11 '13 at 10:51
  • $\begingroup$ Yes, I'm familiar with t- and F-tests. I'd like to show estimated influence, for which afaik t- and F-tests are not suitable. $\endgroup$ – robert Jul 11 '13 at 10:54
  • 1
    $\begingroup$ My question is: Should I use partial R² or the coefficients to show how much influence each factor has on the outcome? I was assuming both to point in the same direction. You are saying that's not true because there is multicollinearity in the data. Alright, so when I want to make a statement such as factor 'young' influences the result x times more/is x times more important than factor 'urban', do I look at partial R² or coefficients? $\endgroup$ – robert Jul 11 '13 at 11:17
  • 1
    $\begingroup$ I do not agree with @IMA. Partial R squared is directly linked to partial correlation, which is a nice way to study confounder-adjusted relations between iv and dv. $\endgroup$ – Michael M Nov 8 '13 at 18:31
  • 1
    $\begingroup$ I edited your question to make it appear on the front page again. I would be very interested in a good answer; if none appears I might even offer a bounty. By the way, regression coefficients after standardizing all predictors are called "standardized coefficients". I put this term into your question, to make it clearer. $\endgroup$ – amoeba Mar 26 '15 at 10:32

In short, I wouldn't use both the partial $R^2$ and the standardized coefficients in the same analysis, as they are not independent. I would argue that it is usually probably more intuitive to compare relationships using the standardized coefficients because they relate readily to the model definition (i.e. $Y = \beta X$). The partial $R^2$, in turn, is essentially the proportion of unique shared variance between the predictor and dependent variable (dv) (so for the first predictor it is the square of the partial correlation $r_{x_1y.x_2...x_n}$). Furthermore, for a fit with a very small error all the coefficients' partial $R^2$ tend to 1, so they are not useful in identifying the relative importance of the predictors.

The effect size definitions

  • standardized coefficient, $\beta_{std}$ - the coefficients $\beta$ obtained from estimating a model on the standardized variables (mean = 0, standard deviation = 1).
  • partial $R^2$- The proportion of residual variation explained by adding the predictor to the constrained model (the full model without the predictor). Same as:

    • the square of the partial correlation between the predictor and the dependent variable, controlling for all the other predictors in the model. $R_{partial}^2 = r_{x_iy.X\setminus x_i}^2$.
    • partial $\eta^2$ - the proportion of type III sums of squares from the predictor to the sum of squares attributed to the predictor and the error $\text{SS}_\text{effect}/(\text{SS}_\text{effect}+\text{SS}_\text{error})$
  • $\Delta R^2$ - The difference in $R^2$ between the constrained and full model. Equal to:

    • squared semipartial correlation $r_{x_i(y.X\setminus x_i)}^2$
    • $\eta^2$ for type III sum of squares $\text{SS}_\text{effect}/\text{SS}_\text{total}$ - what you were calculating as partial $R^2$ in the question.

All of these are closely related, but they differ as to how they handle the correlation structure between the variables. To understand this difference a bit better let us assume we have 3 standardized (mean = 0, sd = 1) variables $x,y,z$ whose correlations are $r_{xy}, r_{xz}, r_{yz}$. We will take $x$ as the dependent variable and $y$ and $z$ as the predictors. We will express all of the effect size coefficients in terms of the correlations so we can explicitly see how the correlation structure is handled by each. First we will list the coefficients in the regression model $x=\beta_{y}Y+\beta_{z}Z$ estimated using OLS. The formula for the coefficients: \begin{align}\beta_{y} = \frac{r_{xy}-r_{yz}r_{zx}}{1-r_{yz}^2}\\ \beta_{z}= \frac{r_{xz}-r_{yz}r_{yx}}{1-r_{yz}^2}, \end{align} The square root of the $R_\text{partial}^2$ for the predictors will be equal to:

$$\sqrt{R^2_{xy.z}} = \frac{r_{xy}-r_{yz}r_{zx}}{\sqrt{(1-r_{xz}^2)(1-r_{yz}^2)}}\\ \sqrt{R^2_{xz.y}} = \frac{r_{xz}-r_{yz}r_{yx}}{\sqrt{(1-r_{xy}^2)(1-r_{yz}^2)}} $$

the $\sqrt{\Delta R^2}$ is given by:

$$\sqrt{R^2_{xyz}-R^2_{xz}}= r_{y(x.z)} = \frac{r_{xy}-r_{yz}r_{zx}}{\sqrt{(1-r_{yz}^2)}}\\ \sqrt{R^2_{xzy}-R^2_{xy}}= r_{z(x.y)}= \frac{r_{xz}-r_{yz}r_{yx}}{\sqrt{(1-r_{yz}^2)}} $$

The difference between these is the denominator, which for the $\beta$ and $\sqrt{\Delta R^2}$ contains only the correlation between the predictors. Please note that in most contexts (for weakly correlated predictors) the size of these two will be very similar, so the decision will not impact your interpretation too much. Also, if the predictors that have a similar strength of correlation with the dependent variable and are not too strongly correlated the ratios of the $\sqrt{ R_\text{partial}^2}$ will be similar to the ratios of $\beta_{std}$.

Getting back to your code. The anova function in R uses type I sum of squares by default, whereas the partial $R^2$ as described above should be calculated based on a type III sum of squares (which I believe is equivalent to a type II sum of squares if no interaction is present in your model). The difference is how the explained SS is partitioned among the predictors. In type I SS the first predictor is assigned all the explained SS, the second only the "left over SS" and the third only the left over SS from that, therefore the order in which you enter your variables in your lm call changes their respective SS. This is most probably not what you want when interpreting model coefficients.

If you use a type II sum of squares in your Anova call from the car package in R, then the $F$ values for your anova will be equal to the $t$ values squared for your coefficients (since $F(1,n) = t^2(n)$). This indicates that indeed these quantities are closely tied, and should not be assessed independently. To invoke a type II sum of squares in your example replace anova(mod) with Anova(mod, type = 2). If you include an interaction term you will need to replace it with type III sum of squares for the coefficient and partial R tests to be the same (just remember to change contrasts to sum using options(contrasts = c("contr.sum","contr.poly")) before calling Anova(mod,type=3)). Partial $R^2$ is the variable SS divided by the variable SS plus the residual SS. This will yield the same values as you listed from the etasq() output. Now the tests and $p$-values for your anova results (partial $R^2$) and your regression coefficients are the same.


  • $\begingroup$ What do you mean by "betas are calculated based on a type III sum of squares"? I thought that regression coefficients are determined in a way that has nothing to do with the choice of SS type; it's always $\beta = (X^\top X)X^\top y$, isn't it? $\endgroup$ – amoeba Mar 27 '15 at 18:58
  • 1
    $\begingroup$ You're right, what I meant was that type III SS and t tests for coefficients give basically the same F test and p value. $\endgroup$ – Chris Novak Mar 27 '15 at 19:02
  • 2
    $\begingroup$ @amoeba after doing some calculations I edited my answer to include your suggestions, clarify the differences between the two effect sizes a bit and better address the OP's answer. $\endgroup$ – Chris Novak Mar 28 '15 at 22:29
  • 1
    $\begingroup$ @amoeba I've updated my response as suggested. Now that I think about it it makes more sense to compare standardized coefficients or $\Delta R^2$ than partial $R^2$. It makes little sense to compare partial $R^2$ for example adding a predictor, that is uncorrelated to the other predictors, changes the ratios (relative importance) of partial $R^2$ between them. $\endgroup$ – Chris Novak Apr 2 '15 at 12:58
  • 1
    $\begingroup$ Thanks, @Chris, your answer improved a lot and by now is pretty excellent (if I were OP, I would accept it). I am not sure I understood your argument in favor of $\Delta R^2$ over $R^2_p$. Adding a predictor uncorrelated to all other predictors, should not change SSeffect for all others (?) but will reduce SSerror. So $\Delta R^2$ will all stay the same, but $R^2_p$ will all increase and their ratios might change; is that what you meant? Here is another argument: if the model is perfect and SSerror is zero, then partial $R^2$ will equal to $1$ for all predictors! Not very informative :) $\endgroup$ – amoeba Apr 2 '15 at 13:40

As already explained in several other answers and in comments, this question was based on at least three confusions:

  1. Function anova() uses sequential (also called type I) sum of squares (SS) decomposition that depends on the order of predictors. A decomposition corresponding to the regression coefficients and $t$-tests for their significance, is type III SS, that you can obtain with Anova() function from car package.

  2. Even if you use type III SS decomposition, then partial $R^2$ for each predictor are not going to be equal to the squared standardized coefficients $\beta_\mathrm{std}$. The ratios of these values for two different predictors will also be different. Both values are measures of effect size (or importance), but they are different, non-equivalent, measures. They might qualitatively agree most of the times, but they do not have to.

  3. What you called partial R squared is not partial R squared. Partial $R^2$ is defined as $\text{SS}_\text{effect}/(\text{SS}_\text{effect}+\text{SS}_\text{error})$. In contrast, $\text{SS}_\text{effect}/\text{SS}_\text{total}$ can be called "eta squared" (borrowing a term from ANOVA), or squared semipartial correlation, or perhaps semipartial $R^2$ (in both formulas $\text{SS}_\text{effect}$ is understood in the type III way). This terminology is not very standard. It is yet another possible measure of importance.

After these confusions are clarified, the question remains as to what are the most appropriate measures of predictor effect size, or importance.

In R, there is a package relaimpo that provides several measures of relative importance.

mod <- lm(education~income+young+urban, data=Anscombe)
metrics <- calc.relimp(mod, type = c("lmg", "first", "last", "betasq", "pratt", "genizi", "car"))

Using the same Anscombe dataset as in your question, this yields the following metrics:

Relative importance metrics: 

              lmg      last      first    betasq       pratt     genizi        car
income 0.47702843 0.4968187 0.44565951 0.9453764  0.64908857 0.47690056 0.55375085
young  0.14069003 0.1727782 0.09702319 0.1777135  0.13131006 0.13751552 0.13572338
urban  0.07191039 0.0629027 0.06933945 0.1188235 -0.09076978 0.07521276 0.00015460

Some of these metrics have already been discussed:

  • betasq are squared standardized coefficients, the same values as you obtained with lm().
  • first is squared correlation between each predictor and response. This is equal to $\text{SS}_\text{effect}/\text{SS}_\text{total}$ when $\text{SS}_\text{effect}$ is type I SS when this predictor is first in the model. The value for 'income' (0.446) matches your computation based on anova() output. Other values don't match.
  • last is an increase in $R^2$ when this predictor is added last into the model. This is $\text{SS}_\text{effect}/\text{SS}_\text{total}$ when $\text{SS}_\text{effect}$ is type III SS; above I called it "semipartial $R^2$". The value for 'urban' (0.063) matches your computation based on anova() output. Other values don't match.

Note that the package does not currently provide partial $R^2$ as such (but, according to the author, it might be added in the future [personal communication]). Anyway, it is not difficult to compute by other means.

There are four further metrics in relaimpo -- and one more (fifth) is available if the package relaimpo is manually installed: CRAN version excludes this metric due to a potential conflict with its author who, crazy as it sounds, has a US patent on his method. I am running R online and don't have access to it, so if anybody can manually install relaimpo, please add this additional metric to my output above for completeness.

Two metrics are pratt that can be negative (bad) and genizi that is pretty obscure.

Two interesting approaches are lmg and car.

The first is an average of $\text{SS}_\text{effect}/\text{SS}_\text{total}$ over all possible permutations of predictors (here $\text{SS}_\text{effect}$ is type I). It comes from a 1980 book by Lindeman & Merenda & Gold.

The second is introduced in (Zuber & Strimmer, 2011) and has many appealing theoretical properties; it is squared standardized coefficients after predictors have been first standardized and then whitened with ZCA/Mahalanobis transformation (i.e. whitened while minimizing reconstruction error).

Note that the ratio of the contribution of 'young' to 'urban' is around $2:1$ with lmg (this matches more or less what we see with standardized coefficients and semipartial correlations), but it's $878:1$ with car. The reason for this huge difference is not clear to me.


  1. References on relative importance on Ulrike Grömping's website -- she is the author of relaimpo.

  2. Grömping, U. (2006). Relative Importance for Linear Regression in R: The Package relaimpo. Journal of Statistical Software 17, Issue 1.

  3. Grömping, U. (2007). Estimators of Relative Importance in Linear Regression Based on Variance Decomposition. The American Statistician 61, 139-147.

  4. Zuber, V. and Strimmer, K. (2010). High-dimensional regression and variable selection using CAR scores. Statistical Applications in Genetics and Molecular Biology 10.1 (2011): 1-27.

  5. Grömping, U. (2015). Variable importance in regression models. Wiley Interdisciplinary Reviews: Computational Statistics, 7(2), 137-152. (behind pay wall)

  • $\begingroup$ Very nice summary with an additional valuabe info on various importance coefficients. BTW, are you using online this R engine pbil.univ-lyon1.fr/Rweb or another one? $\endgroup$ – ttnphns Apr 1 '15 at 9:41
  • 1
    $\begingroup$ I use r-fiddle.org, but I never tried anything else and don't know how it compares. It looks pretty sleek though. $\endgroup$ – amoeba Apr 1 '15 at 9:54
  • $\begingroup$ Very clear summary and additional info on effect sizes (+1) $\endgroup$ – Chris Novak Apr 1 '15 at 10:16

You wrote:

My question is: Should I use partial R² or the coefficients to show how much influence each factor has on the outcome?

It is important not to confuse two things here. First, there is the question of model specification. The lm algorithm assumes that the OLS-assumptions are met. Among other things this means that for unbiased estimates, NO signficant variable can be missing from the model (except for when it is uncorrelated to all other regressors, rare).
So in finding a model, the additional influence on R² or adjusted R² is of course of interest. One might think it is proper to add regressors until the adjusted R² stops improving, for example. There are interesting problems with stepwise regression procedures such as this, but this is not the topic. In any case I assume there was a reason you chose your model.

HOWEVER: this additional influence on the R² is not identical to the real or total influence of the regressor on the independent variable, precisely because of multicollinerity: If you take away the regressor, part of its influence will now be attributed to the other regressors which are correlated to it. So now the true influence is not correctly shown.

And there is another problem: The estimates are only valid for the complete model with all other regressors present. Either this model is not yet correct and therefore discussion about influence is meaningless - or it is correct and then you can not eliminate a regressor and still use the OLS methods with success.

So: is your model and the use of OLS appropriate? If it is, then the estimates answer your question - they are your literal best guess of the influence of the variables on the regressand / dependent variable.
If not, then your first job is to find a correct model. For this the use of partial R² may be a way. A search on model specification or stepwise regression will produce a lot of interesting approaches in this forum. What works will depend on your data.

  • 1
    $\begingroup$ Thank four your answer! I am not sure your statement that "this additional influence on the R² is not identical to the real or total influence of the regressor on the independent variable" is uncontroversial. Package relaimpo cran.r-project.org/web/packages/relaimpo/relaimpo.pdf for example uses partial R² "for assessing relative importance in linear models". $\endgroup$ – robert Jul 11 '13 at 12:15
  • 1
    $\begingroup$ Do you think you could provide a reference for your view that R² should only be used for model selection? $\endgroup$ – robert Jul 12 '13 at 9:51
  • 1
    $\begingroup$ @robert: The raison d'etre of relaimpo is to provide alternatives to partial R^2, for exactly the reason IMA gives! $\endgroup$ – Scortchi - Reinstate Monica Mar 30 '15 at 17:19
  • 1
    $\begingroup$ @Scortchi: Wow, after looking in the manual of the relaimpo package I realized that there is a whole world of different approaches to quantifying relative importance of predictors in linear regression. I am currently looking through some papers linked there (this 2010 preprint looks pretty good so far), and this is a mess! I did not realize that this issue is so complicated, when I offered my bounty. It doesn't seem to have been properly discussed on CV. Is this an obscure topic? If so, why? $\endgroup$ – amoeba Mar 31 '15 at 15:14
  • 2
    $\begingroup$ @amoeba: An off-the-cuff answer is that "relative importance of predictors" isn't all that important for most purposes. If you have a model you're happy with then you can use it to say things like smoking one cigarette a day is equivalent to eating five hamburgers in terms of the risk of getting a heart attack - the importance comes from the substantive interpretation of what you're modelling; if you're comparing models you compare whole models - say ones with & without an expensive-to-measure pair of predictors - & don't need to worry about how predictive power might be fairly divvied up. $\endgroup$ – Scortchi - Reinstate Monica Mar 31 '15 at 16:47

Regarding the difference between the linear regression coefficient and the partial correlation you may read this, for example.

However, the confusion expressed in the question seems to be of another nature. It appears to be about the default type of sums-of-squares used by this or that statistical package (topic, repeatedly discussed on our site). Linear regression uses what is called in ANOVA Type III SS reckoning. In many ANOVA programs that is the default option too. In R function anova, it appears to me (I'm not R user, so I just suppose it) the default reckoning is Type I SS (a "sequential SS" which is dependent on the order the predictors are specified in the model). So, the discrepancy that you observed and which did not dissapear when you standardized ("scaled") your variables is because you specified the ANOVA with the default Type I option.

Below are results obtained in SPSS with your data:

enter image description here enter image description here enter image description here enter image description here

You may pick in these print-outs that parameters (regressional coefficients) are the same regardless type of SS calculation. You may notice also that partial Eta squared [which is SSeffect/(SSeffect+SSerror) and = partial R-squared in our case because the predictors are numeric covariates] is fully the same in the table of effects and of coefficients only when type SS is III. When type SS is I, only the last of the 3 predictors, "urban", retains the same value (.169); this is because in the sequence of input of the predictors it is the last. In case of type III SS the order of input does not matter, as in regression. By the way, the discrepancy is obseved in p-values as well. Although you don't see it in my tables because there is only 3 decimal digits in "Sig" column, the p-values are different between parameters and effects - except for the last predictor or except when type of SS is III.

You might want to read more about different "SS types" in ANOVA / linear model. Conceptually, type III or "regression" type of SS is fundamental and primordial. Other types of SS (I, II, IV, there exist even more) are special devices to estimate the effects more comprehensively, less wastefully than regression parameters allow in the situation of correlated predictors.

Generally, effects sizes and their p-values are more important to report than parameters and their p-values, unless the aim of the study is to create model for the future. Parameters are what allow you to predict, but "influence" or "effect" may be a wider concept than "strength of linear prediction". To report influence or importance other coefficients are possible besides the partial Eta squared. One being is the leave-one-out coefficient: the importance of a predictor is the residual sum of squares with the predictor removed from the model, normalized so that the importance values for all the predictors sum to 1.

  • $\begingroup$ +1, thanks for joining the discussion. I have a terminological question. "Partial R squared" is defined as SSeffect/(SSeffect+SSerror). What is the name for SSeffect/SStotal? As far as I understand (correct me if I am wrong), if we use type III SS decomposition, then this SSeffect/SStotal will be equal to squared partial correlation between response and this predictor (controlling for all other predictors). Does this quantity have a name? Partial R2 is analogous to partial eta squared, but why is there no name for the analogue of eta squared itself? I am confused by this. $\endgroup$ – amoeba Mar 31 '15 at 22:27
  • $\begingroup$ Oops, I think I wrote some nonsense above: squared partial correlation is SSeffect/(SSeffect+SSerror), i.e. exactly partial R2, correct? Still, the question about how to call SSeffect/SStotal (which is what OP tried to compute in his original question!) remains. Should we just call it eta squared? Or "partitioned R2" (understanding of course that for type III SS, these "partitions" will not sum to the total R2)? $\endgroup$ – amoeba Mar 31 '15 at 23:00
  • 1
    $\begingroup$ Yes, SSeffect/SStotal is simply eta squared. It is eta squared of the predictor in that specific model (not to confuse with marginal eta squared = eta squared when the predictor is only one in the model = zero-order Pearson r^2, in our case of continuous predictors). $\endgroup$ – ttnphns Apr 1 '15 at 3:46
  • 1
    $\begingroup$ Exactly so. Part correlation is (a specific instance of) eta. I think that it is proper therefore to call that eta in the model part eta. I just don't remember any text where I encounter the term "part" or "semipartial" eta. If you find out it, please let me know. $\endgroup$ – ttnphns Apr 1 '15 at 9:04
  • 1
    $\begingroup$ Yes; why, I think the same way. But r, partial r, semipartial r are particular cases ot the corresponding eta. The important terminologic distinction between the two, however, arises in the context when, besides, the overall categorical (dummy) "nonlinear" effect we add linear (or polynomial) effect of the predictor as if numeric-coded. Here we display 3 effects: Combined Etasq = Linear Rsq + Deviation-from-linearity. $\endgroup$ – ttnphns Apr 1 '15 at 10:30

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.