Let's work it out.
The logarithm of the Dirichlet density function is
$$\lambda(\mathbf{x}|\mathbf{\alpha}) = \log(\Gamma(\alpha_0)) - \sum_{i=1}^{k}{\log(\Gamma(\alpha_i)))} + \sum_{i=1}^{k}{(\alpha_i - 1)\log(x_i)},$$
where $\alpha_0 = \alpha_1 + \alpha_2 + \cdots + \alpha_k$.
Taking second partial derivatives with respect to the parameters $\alpha_i$ is particularly simple; all we really need to know (in addition to the most basic properties of derivatives) is that $\partial \alpha_0 / \partial \alpha_i = 1$ and $\partial x_j / \partial \alpha_i = 0$. Thus
$$\frac{\partial \lambda}{\partial \alpha_i} = \psi(\alpha_0) - \psi(\alpha_i) + \log(x_i)$$
and
$$\frac{\partial^2 \lambda}{\partial \alpha_i \partial \alpha_j}
= \psi'(\alpha_0) - \psi'(\alpha_j)\delta_{i j},$$
where $\psi$ (the digamma function) is the derivative of $\log(\Gamma)$ and $\delta_{i j} = 1$ if and only if $i = j$ and is $0$ otherwise: that is, it's the $k$ by $k$ identity matrix. The Fisher Information Matrix is, by definition, the negative expectation of the matrix of second partial derivatives. Because its entries are constant with respect to the random variable $\mathbf{x}$, taking expectations is trivial. We obtain a matrix with the values $\psi'(\alpha_i)$ along the diagonal and $\psi'(\alpha_0)$ is subtracted everywhere, showing that @onestop's interpretation is correct. ("$PG(1,\alpha)$" is merely an idiosyncratic notation for the polygamma function $\psi'(\alpha)$.)