A famous car production company produces 3 different models of cars, available in 5 colors and 3 possible CC(1900 cc,2000 cc and 2200 cc). suppose that every combination of model, color and CC has equal probability to be selected by a client:
- If in one week 6 cars are sold, what is the probability that at least two cars are equal(same color,cc, and model)
My answer: Total possible combinations are 45^6, instead of finding "at least" two cars i would find 1-(Probability to get zero equal cars + probability to get one equal car) :
P(get 0 equal cars)= 44^6 P(Get 1 equal cars) 44^5
So the answer is: $1-(44^6+44^5/45^6)= 1-0.893= 0.107$
Is my answer correct?