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hopefully you can help me with the meaning of the following, I don't really understand the terminology: "regression of a vector of ones on the matrix $W$", where $W$ is something like $(W_t)' = (w_{1t},w_{2t},w_{3t}, w_{4t})$.

I don't understand, which regression I actually have to compute. If it is of help for you, I'm trying to understand the Godfrey/Wickens test according to this article: Ghosh, S., Gilbert, C. L., & Hallett, A. J. H. (1983). Empirical Economics, 8, 63–69. DOI: 10.1007/BF01973190

Greeting, Julius

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  • $\begingroup$ Would be great if you cited whole passage where this occurs. It should be something simple, but I do not have access to the article, so I cannot answer. For example it might mean regression where dependent variable is vector of ones and independent variables are the columns of $W_t$. Usually further formulas in article give hints what authors had in mind. $\endgroup$
    – mpiktas
    Mar 1, 2011 at 14:38
  • $\begingroup$ Thanks for comment. I put up the first three pages here, hoping not to violate any rights too much, but I fear the paragraph is not understandable without the rest (img815.imageshack.us/i/paper0.jpg, img339.imageshack.us/i/paper1d.jpg, img683.imageshack.us/i/paper2a.jpg). The interesting part is on the third page and I don't really see any further information :( Unfortunately I don't have access to the original article by Godfrey and Wickens mentioned there. $\endgroup$
    – Askan
    Mar 1, 2011 at 17:21
  • $\begingroup$ @Askan Those ImageShack links appear no longer to be hosted. $\endgroup$
    – whuber
    Jan 20, 2015 at 22:46

1 Answer 1

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Ordinary least squares regression of $y$ on $X$ involves solving the normal equations $$X'X\hat{\beta} = X'y$$ for $\hat{\beta}$, so I'd assume OLS regression of a vector of ones on $W$ implies solving $$W'W\hat{\beta} = W'\bf{1},$$ where $\bf{1}$ is a vector of ones. If the matrix $X$ itself contained a column of ones, i.e. if the RHS of the regression included a constant, then the solution would be trivial, so I assume none of the $w_{it}$'s are constant in your case.

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  • $\begingroup$ +1, it is basically the same as my comment, but much nicer written. $\endgroup$
    – mpiktas
    Mar 1, 2011 at 15:15
  • $\begingroup$ I spent too long LaTeXing that so i didn't see your comment before I submitted this answer. It appears that when you're writing an answer SE alerts you to other answers being posted, but not comments. $\endgroup$
    – onestop
    Mar 1, 2011 at 15:23
  • $\begingroup$ Thanks for your explanation, I think I now understand, although I had to reject this anyway as it doesn't fit my needs. $\endgroup$
    – Askan
    Mar 8, 2011 at 12:06

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