I'm trying to understand how the parameters are estimated in ARIMA modeling/Box Jenkins (BJ). Unfortunately none of the books that I have encountered describes the estimation procedure such as Log-Likelihood estimation procedure in detail. Following is the Log-Likelihood for ARMA from any standard textbooks: $$ LL(\theta)=-\frac{n}{2}\log(2\pi) - \frac{n}{2}\log(\sigma^2) - \sum\limits_{t=1}^n\frac{e_t^2}{2\sigma^2} $$
I want to learn the ARIMA/BJ estimation by doing it myself. So I used $R$ to write a code for estimating ARMA by hand. Below is what I did in $R$,
- I simulated ARMA (1,1)
- Wrote the above equation as a function
- Used the simulated data and the optim function to estimate AR and MA parameters.
- I also ran the ARIMA in the stats package and compared the ARMA parameters from what I did by hand. Below is the comparison:
**Below are my questions:
- Why is there a slight difference between the estimated and calculated variables ?
- Does ARIMA function in R backcasts or does the estimation procedure differently than what is outlined below in my code?
- I have assigned e1 or error at observation 1 as 0, is this correct ?
- Also is there a way to estimate confidence bounds of forecasts using the hessian of the optimization ?
Thanks so much for your help as always.
Below is the code:
## Load Packages
library(stats)
library(forecast)
set.seed(456)
## Simulate Arima
y <- arima.sim(n = 250, list(ar = 0.3, ma = 0.7), mean = 5)
plot(y)
## Optimize Log-Likelihood for ARIMA
n = length(y) ## Count the number of observations
e = rep(1, n) ## Initialize e
logl <- function(mx){
g <- numeric
mx <- matrix(mx, ncol = 4)
mu <- mx[,1] ## Constant Term
sigma <- mx[,2]
rho <- mx[,3] ## AR coeff
theta <- mx[,4] ## MA coeff
e[1] = 0 ## Since e1 = 0
for (t in (2 : n)){
e[t] = y[t] - mu - rho*y[t-1] - theta*e[t-1]
}
## Maximize Log-Likelihood Function
g1 <- (-((n)/2)*log(2*pi) - ((n)/2)*log(sigma^2+0.000000001) - (1/2)*(1/(sigma^2+0.000000001))*e%*%e)
##note: multiplying Log-Likelihood by "-1" in order to maximize in the optimization
## This is done becuase Optim function in R can only minimize, "X"ing by -1 we can maximize
## also "+"ing by 0.000000001 sigma^2 to avoid divisible by 0
g <- -1 * g1
return(g)
}
## Optimize Log-Likelihood
arimopt <- optim(par=c(10,0.6,0.3,0.5), fn=logl, gr = NULL,
method = c("L-BFGS-B"),control = list(), hessian = T)
arimopt
############# Output Results###############
ar1_calculated = arimopt$par[3]
ma1_calculated = arimopt$par[4]
sigmasq_calculated = (arimopt$par[2])^2
logl_calculated = arimopt$val
ar1_calculated
ma1_calculated
sigmasq_calculated
logl_calculated
############# Estimate Using Arima###############
est <- arima(y,order=c(1,0,1))
est
g1
. You need to dispense with the+0.000000001
stuff, too, even though that changes the answer only a little: for small $\sigma$ it will ensure you report incorrect values of this parameter. $\endgroup$